2道分式题1.2x²+4xy+2y²/x²-xy+2y²=2(x+y)/( )2

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/15 17:34:35

2道分式题
1.2x²+4xy+2y²/x²-xy+2y²=2(x+y)/( )
2.3x²-xy/9x²-6xy+y²=x/( )=( )/9x²-y²

1、
2、3x²-xy/9x²-6xy+y²
=x(3x-y)/(9x²-y²-6xy+2y²)
=x(3x-y)/[(3x-y)(3x+y)-2y(3x-y)]
=x/(3x-y)
=x(3x+y)/[(3x-y)(3x+y)]
=x(3x+y)/(9x²-y²)

x/y=2,求分式x²-xy+3y²/x²+xy+6y² 1-x²+2xy-y² x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy 代数分式一道题若x÷y=2,则分式（x²-xy+3y²)÷（x²＋xy＋6y² 分式的除法运算x²－4y²/x²+y²+2xy÷2y+x/x²+xy 计算:(1).(-2xy²)*(3x²y)² 分式的乘除法计算：：x²-4y²/x²+2xy+y²÷x+2y/x²+ 已知x/y=3,求x²+2xy-3y²/x²-2xy+y² 已知x/y=3,求x²+2xy-3y²/x²-xy+y²的值 |x+2y+3|+(2x+y)²=0求x²-xy+y² 先化简,再求值：3xy²(-x²y+2x³y²)-4xy(-xy²)· 若x/y=2,求分式(x²-xy+3y²)/(x²+xy+6y²)的值