x²y²-x²-y²+1 x²-2x-4y²-4y
(2x-y)²-4(x-y)(x+2y)
化简:(2x-y)²-4(x-y)(x+y)
已知x²+y²+5=2x+4y,求【2x²-(x-y)(x-y)】【(x+y-1)(x-y
(x-2y)²+(2x-4y)(x+y)+(x+y)²
(x+y)²+4(x+y)-5
[(y-2x)(-2x-y)-4(x-2y)²]*2y,其中x=1,y=2
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²
(x+y)和(x-y)各看成一个整体,合并同类项2(x+y)-3(x-y)²+3(x+y)+4(x-y)
已知x²+y²+5=2x+4y,求代数式(2x²-(x+y)(x-y))x((x+y-1)
因式分解:x²(x-y)+(y-x)
多项式因式分解 1,(x-y)³-(x-y)²(x+y) 2,x(x²-xy)-(4x