线性代数组通解设A=(a1,a2 ,a3 ,a4)是四阶方阵,ai是四维列向量.若a2,a3,a4线性无关,β=a1+a

设矩阵A=(a1,a2,a3,a4),其中a2,a3,a4线性无关,a1=2a2-a3,向量b=a1+a2+a3+a4, 设矩阵A=(a1,a2,a3,a4）其中a2,a3,a4线性无关,a1=2a2-a3,向量b=a1+a2+a3+a4,求 已知四阶方阵A=（a1,a2,a3,a4),a1,a2,a3,a4均为四维列向量,其中a2,a3,a4线性无关,a1=2 设矩阵A=[a1.a2.a3.a4],其中a2.a3.a4线性无关,a1=2a3-3a4.向量b=a1+2a2+3a3+ 设A=(A1,A2,A3,A4),其中列向量A1,A2,A3线性无关,且A4=A1-A2+2A3,则齐次线性方程组AX= 已知四阶方阵且A=(a1,a2,a3,a4),其中a1,a2,a3,a4线性无关,且a1=2a2-a3,B=a1+a2+ 线性相关选择题2题：设向量组a1,a2,a3,a4线性无关,则有 A a1,a3,a4线性无关 B a1,a4线性无关& 设A=(a1,a2,a3,a4),ai(i=1,2,3,4)为5维向量,若a2,a3,a4线性无关,且a4=a1+2a2 设向量组a1,a2,a3,a4,a5线性相关,而向量组a2,a3,a4,a5线性无关,则向量组a1,a2,a3,a4,a 设A=(a1,a2,a3,a4),ai(i=1,2,3,4)为5维列向量,若a2,a3,a4线性无关,且a4=a1+2a 设n维向量a1 a2线性无关a3 a4线性无关若a1 a2都分别与a3 a4正交 证明a1 a2,a3,a4线性无关 若向量a1,a2,a3,a4线性无关,则下列向量先行无关的是：(A)a1+a2,a2+a3,a3+a4,a4+a1