(x-1)(x-2)(x-3)(x-4)-(x^2-5x)^2-10(x^2-5x)怎么算?
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/23 19:24:22
(x-1)(x-2)(x-3)(x-4)-(x^2-5x)^2-10(x^2-5x)怎么算?
(x-1)(x-2)(x-3)(x-4)-(x^2-5x)^2-10(x^2-5x) =[(x-1)(x-4)(x-2)(x-3)]-(x^2-5x)^2-10(x^2-5x) =(x^2-5x+4)(x^2-5x+6)-(x^2-5x)^2-10(x^2-5x) ==[(x^2-5x)+4][(x^2-5x)+6]-(x^2-5x)^2-10(x^2-5x) =(x^2-5x)^2+10(x^2-5x)+24-(x^2-5x)^2-10(x^2-5x) =24
|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10|
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设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10),
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x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少?
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550
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1X?+2X?+3X?+4X?+5X?+6X?+7X?+8X?+9X?+10X?=1980求?是多少
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