计算①(2x+y-3z)²;②y(x+y)+(x-y)²-x²-2y².
来源:学生作业帮 编辑:作业帮 分类:综合作业 时间:2024/06/05 23:58:26
计算①(2x+y-3z)²;②y(x+y)+(x-y)²-x²-2y².
①(2x+y-3z)²
=(2x+y)²-6z(2x+y)+9z²
=4x²+4xy+y²-12xz-6yz+9z²
②y(x+y)+(x-y)²-x²-2y²
=xy+y²+x²-2xy+y²-x²-2y²
=-xy
再问: 1.��|x+y-5|+(xy-6)²=0������x²+y²��ֵ�� 2.��֪��m-n)²=8����m+n��²=2����m²+n²=
再答: 1、x+y-5=0 xy=6 ∴x+y=5 x²+y²=(x+y)²-2xy=5²-12=13 2、由(1)得 m²-2mn+n²=8 (3) 由(2)得 m²+2mn+n²=2 (4) (3)+(4)得 2m²+2n²=10 ∴m²+n²=5
=(2x+y)²-6z(2x+y)+9z²
=4x²+4xy+y²-12xz-6yz+9z²
②y(x+y)+(x-y)²-x²-2y²
=xy+y²+x²-2xy+y²-x²-2y²
=-xy
再问: 1.��|x+y-5|+(xy-6)²=0������x²+y²��ֵ�� 2.��֪��m-n)²=8����m+n��²=2����m²+n²=
再答: 1、x+y-5=0 xy=6 ∴x+y=5 x²+y²=(x+y)²-2xy=5²-12=13 2、由(1)得 m²-2mn+n²=8 (3) 由(2)得 m²+2mn+n²=2 (4) (3)+(4)得 2m²+2n²=10 ∴m²+n²=5
计算3x[xy-2x(1/y-x/3]+3y(x²-y²)
计算(x²/x+2y)-x+2y-2
若x-y=6,xy=-8,求代数式(x+y+z)²+(x-y-z)(x-y+z)-2·z(x+y)的值
(2x-y)²-4(x-y)(x+2y)
化简:(2x-y)²-4(x-y)(x+y)
(x-3y+2z)²=
[(3x+y)²-(3x-y)²]÷(4x-2y)计算 怎么做?
(2x-3y)²-4z² x²-y²-2y-1
数学用乘法公式计算(x+y+1)(x+y-1)(2x-y-3)²
(x-y)·2(x-y)²·3(x-y)³ 计算
计算 (1)(-3x³y/2z²)²
计算:3x-2y- [-4x+(z+3y)]