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欲配置0.5mol/L的稀Hcl 500ml,需用37%(p=1.19)的浓Hcl多少ml?

来源:学生作业帮 编辑:作业帮 分类:综合作业 时间:2024/05/23 11:29:16
欲配置0.5mol/L的稀Hcl 500ml,需用37%(p=1.19)的浓Hcl多少ml?
请写清楚点,
37%=c1(HCl)*M(HCl)/p
c1(HCl)=p*37%/M(HCl)
=1190g/l*37%/36.5g/mol
=12.06mol/l
又c1(HCl)V1=c2(HCl)V2
所以V1=c2(HCl)*V2/c1(HCl)
=0.5*500/12.06ml
=20.73ml
及欲配置0.5mol/L的稀Hcl 500ml,需用37%(p=1.19)的浓Hcl 20.73ml