x²+2/2x²-1减3(2x²-1)/x²+2

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/23 00:27:05

x²+2/2x²-1减3(2x²-1)/x²+2
x²+2/2x²-1减3(2x²-1)/x²+2=-2

(3-√2)/3
再问：是真的吗
再答： x^2=(7-√31)/6
再问：有过程吗
再答：设x^2=y,(y+2)/(2y-1)-3(2y-1)/(y+2)=-2,两边乘以(y+2)/(2y-1)，,(y+2)^2-3(2y-1)^2=-2(y+2)/(2y-1),y整理得7y^2-22y+3=0,y=1/7或21/7

(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3 6x+(2x²-3x)-(x²-1) （2x²-2x+3)(-x³+x-1) x²+3x+9/(x²-27)+6x/(9x-x²)-(x-1)/(6+2x) (x+1)/(x²+3x+2)+(x²-2x)/(x²-4) x(x²-1)+2x²（x+1)-3x（2x-5)计算 (x-1)(2x²-3x+2)-x(x+1)(x-2) ①2(x+3)(x-3)=x²+(x-1)(x+1)+2x 根号x²-2x+1（x 不等式x²-2x-2/x²+x+1 化简（x+1/x)²+2（x+1/x)+2 (4x³)²×[x³-x(2x-1)]