{x+y+z=10{2x+3y+z=17{3x+2y-z=8的解
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
x/2=y/3=z/5 x+3y-z/x-3y+z
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
解三元一次方程:x+y-z=0,2x+y+z=7,x-3y+z=8
解方程组2x+y-3z=1,x-2y+z=6,3x-y+2z=9求x,y,z的值
已知4x-3y+z=0,x+2y-8z=0,xyz不等于0,求x+y-z/x-y+2z的值
已知x^3+y^3-6x+2y+z+3+10=0,求(x-y+z)(x+y-z)的值.(z+3)是绝对值
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3
x/10 = y/8 =z/9 求x+2y+3z/y-5z
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
解三元一次方程组 {x+2y=10 y-z=-3 2z-x=8 则2x+y-z的值的