设y=y(x)可微,dy=f'x'dx=f'(x)△x,问dy与△x的关系
设F(x)可导,y=f(x^2),则dy/dx=?
设f(x)为可导函数,y=sin{f[sinf(x)]} dy/dx=
设f(x)可导,求dy/dx y=sin f(x²)
设f x 为可导函数,y=f^2(x+arctanx),求dy/dx
设f(x)为可导函数,求dy/dx:y=f(arcsin(1/x))
设f(x)可导,且y=f(x²)+f[f(x)],求dy/dx
设f(x)=1/x,y=f[(x-1)/(x+1)],求dy/dx
设函数y=f((x^2)*arccosx+tanx)可微,则dy/dx=
设函数f(x)可导,且y=f(x2),则 dy/dx=?
设函数f(x)可导,y=f(x的3次方)则dy/dx是?
y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy
f'(x)=△y/△x 微分dy=f'(x)dx就可以移动dx来求导数,△x与dx的区别是