cosπ/12乘以sinπ/12
化简f(x)=sin(x/2+π/12)乘以cos(x/2+π/12)-cosx/2乘以cosx/2
cos*π/12—sin*π/12
计算cosπ/12*sinπ/12
求值:sin(π/12)+cos(π/12)
(cosπ/12-sinπ/12)*(COSπ/12+sinπ/12)等于
cos(α-π)除以sin(π减α)乘以sin(α-2π)乘以cos(2π-α)化简
cos sin π √
sinπ/24*cosπ/24*sinπ/12=—— 答案是这么写的:1/2(2sinπ/24*cosπ/24)cosπ
已知α=7/12π,那么cosα√(1-sinα)/(1+sinα)+sinα√(1-cosα)/(1-cosα)=
Sin(x+π/3)+2Sin(x-π/3)-根号3乘以Cos(2π/3 -x ) 化简化简
根号3×cosπ/12-sinπ/12=?
高中数学题sinπ/12·cosπ/12