(22x+1)/(x-1)=22+23/(x-1)
若1+x+x*x+x*x*x=0,求x+x*x+x*x*x+.+x(2000次幂)
(x/x-1)+(5x-2)/x*x-x=1 求x(有图)
①(x+4x+8)+3x(x+4x+8)+2x②(2x-3x+1)-22x+33x-1③(6x-1)(2x-1)(3x-
(4x+2)/x+(4x-22)/(x-5)=(x-6)/(x-4)+(7x+9)/(x+1)
[x(x+1)+x平方(x-1)]+(-3x)
解方程X*X+39=(X+1)*(X+1)-22
已知函数f(x)={-x^2+(1/2)x,x
(1) x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8
3/x-1=4/x 6/x+1=x+5/x(x+1)
函数的表示法 f(x+1/x)=x*x+1/(x*x)
(x)-2x·x-x-2x+1=0求x的值,
x-1/4x=1/2 16x(3-2/9) x-0.8x=22