已知x^2+4y^2-2x-2x+8y+5=0,求x^2-y^2/2x^2+xy-y^2*2y-y/xy-y/(x^2+
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/13 16:57:08
已知x^2+4y^2-2x-2x+8y+5=0,求x^2-y^2/2x^2+xy-y^2*2y-y/xy-y/(x^2+y^2/y)^2的值
x²+4y²-2x+8y+5=0
(x-1)²+(2y+2)²=0
得 x=1,y=-1
则 x²-y²/2x²+xy-y²*2y-y/xy-y/(x²+y²/y)²
=1-1/2-1+2-1+1/4
=1/2+1/4
=3/4
再问: 已知x^2+4y^2-2x-2x+8y+5=0,求x^4-y^4/2x^2+xy-y^2*2y-y/xy-y/(x^2+y^2/y)^2的值
再答: x^2+4y^2-2x+8y+5=0 (x-1)²+(2y+2)²=0 得 x=1,y=-1 则 x^4-y^4/2x^2+xy-y^2*2y-y/xy-y/(x^2+y^2/y)^2 =1-1/2-1+2-1+1/4 =3/4
(x-1)²+(2y+2)²=0
得 x=1,y=-1
则 x²-y²/2x²+xy-y²*2y-y/xy-y/(x²+y²/y)²
=1-1/2-1+2-1+1/4
=1/2+1/4
=3/4
再问: 已知x^2+4y^2-2x-2x+8y+5=0,求x^4-y^4/2x^2+xy-y^2*2y-y/xy-y/(x^2+y^2/y)^2的值
再答: x^2+4y^2-2x+8y+5=0 (x-1)²+(2y+2)²=0 得 x=1,y=-1 则 x^4-y^4/2x^2+xy-y^2*2y-y/xy-y/(x^2+y^2/y)^2 =1-1/2-1+2-1+1/4 =3/4
已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值?
已知3x^2+xy-2y^2=0,求{(x+y)/(x-y)+4xy/(y^2-x^2)}/{(x+3y)*(x-y)}
已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²
已知x,y>0 2x+y+3=xy 求5x+4y最小值
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*
已知x+y=-1,xy=-2,求代数式-5(x+y)+(x-y)+x(xy+y)的值
已知3x*+xy-2y*=0,求(x/y)-(y/x)-(x*+y*)/(xy)的值.*是平方
已知x²+y²-2x+4y+5=0,求X^4-y^4/2x^2+xy-y²·2x-y/xy
已知x+4y-2x+8y+5=0,求x^4-y^4/2x+xy-y·2x-y/xy-y÷(x+y/y)的值.
已知xy=-2,x-y=3,求(x+y)(x-y)-y^2+(x-y)^2-(6x^2y-2xy^2)÷2y
因式分解:x×x-xy-2y×y-x-y
已知x-3y=0,求(2x+y)/(x^2-2xy+y^2)X(x-y)