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为什么(x-2y)(x+4y)-(x-2y)+3(x+4y)-3=(x-2y+3)(x+4y-1).

来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/05/07 07:29:42
为什么(x-2y)(x+4y)-(x-2y)+3(x+4y)-3=(x-2y+3)(x+4y-1).
答：
(x-2y)(x+4y)-(x-2y)+3(x+4y)-3
=[(x-2y)(x+4y)+3(x+4y)] - [(x-2y)+3]
=(x+4y)(x-2y+3)- (x-2y+3)
=(x+4y-1)(x-2y+3)
=(x-2y+3)(x+4y-1)
提取公因式的过程
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 (x+3y-4)(2x-y) x/x-y*y^2/x+y-x^3y2/x^4-y^4/x^2/x^2+y^2 化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1 （x+2)(x+3) (x-4)(x+1) (y+4)(y-2) (y-5)(y-3) x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20 {(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20 4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6 3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27 (x+y)(x+2y)(x+3y)(x+4y)=-40 已知x=1/3,y=-1/2,求代数式x-(x+y)+(x+2y)-(x+3y)+(x+4y)-(x+5y)+...-( (2x+y)(2x-3y)+x(2y+y) 2a(x-y)-4b(x-y)