X²-1分之X²-2X除以(X+1分之2X-1减X+1)当X等于2时,求值
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/21 13:02:34
X²-1分之X²-2X除以(X+1分之2X-1减X+1)当X等于2时,求值
(x^2-2x)/(x^2-1)÷[(2x-1)/(x+1)-x+1]
=(x^2-2x)/(x^2-1)÷[(2x-1)/(x+1)-(x-1)(x+1)/(x+1)]
=(x^2-2x)/(x^2-1)÷[(2x-1)/(x+1)-(x^2-1)/(x+1)]
=(x^2-2x)/(x^2-1)÷[(2x-1-x^2+1)/(x+1)]
=(x^2-2x)/(x^2-1)÷[(2x-x^2)/(x+1)]
=(x^2-2x)/(x^2-1)*(x+1)/(2x-x^2)
=(x^2-2x)/(x^2-1)*[-(x+1)/(x^2-2x)]
=-(x+1)/(x^2-1)
=-(x+1)/[(x-1)(x+1)]
=-1/(x+1)
=-1/(2+1)
=-1/3
=(x^2-2x)/(x^2-1)÷[(2x-1)/(x+1)-(x-1)(x+1)/(x+1)]
=(x^2-2x)/(x^2-1)÷[(2x-1)/(x+1)-(x^2-1)/(x+1)]
=(x^2-2x)/(x^2-1)÷[(2x-1-x^2+1)/(x+1)]
=(x^2-2x)/(x^2-1)÷[(2x-x^2)/(x+1)]
=(x^2-2x)/(x^2-1)*(x+1)/(2x-x^2)
=(x^2-2x)/(x^2-1)*[-(x+1)/(x^2-2x)]
=-(x+1)/(x^2-1)
=-(x+1)/[(x-1)(x+1)]
=-1/(x+1)
=-1/(2+1)
=-1/3
当x等于1949时求代数式x²-4分之x²-4x+4÷x+2分之x²-2X+x分之一+1
(x²-5x+6分之x²-3x+2)²/(x²-2x-3分之x-1)²
先化简,再求值:x分之x+1除以(x-2x分之1+x²),其中x=根号2+1
先化简再求值x²-x/(x+1)×x²-1/(x²-2x+1)
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当K为何值时,关于X的方程X+1分之2X减X²+X分之K=X分之X+1
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x+2分之x²-1除以x+2分之1减去1,其中x=3分之1
x+2分之1减去x²-4分之4x减去x-2分之2
已知x²+1=2x,两边同时除以x后,得(x+x分之1)²=2²,用完全平方公式展开,可得
x²-1分之x²+x,化简
2(x²-1²)