输入 1 2 3 4 5 6 7 8 9 输出 一个三乘三的矩阵 第一层 1 2 3 第二层 4 5 6 第三层 7 8

输入 1 2 3 4 5 6 7 8 9 输出 一个三乘三的矩阵 第一层 1 2 3 第二层 4 5 6 第三层 7 8 9 还有 3*3矩阵 每行的和 每列的和
1 2 3 4 5 6 7 8 9 只是例子 其实是9个输入数字

这样行不行?
public class Sss {
\x05public static void main(String args[]) {
\x05\x05int[][] array = new int[][] { { 1,2,3 },{ 4,5,6 },{ 7,8,9 } };
\x05\x05int[] sums = new int[3];
\x05\x05int sum = 0;
\x05\x05for (int i = 0; i < 3; i++) {
\x05\x05\x05for (int j = 0; j < 3; j++) {
\x05\x05\x05\x05sums[j] += array[i][j];
\x05\x05\x05\x05sum += array[i][j];
\x05\x05\x05\x05System.out.print(array[i][j] + "\t");
\x05\x05\x05}
\x05\x05\x05System.out.println(sum);
\x05\x05}
\x05\x05for (int i = 0; i < 3; i++) {
\x05\x05\x05System.out.print(sums[i] + "\t");
\x05\x05}
\x05}
}
再问： Enter the voltage readings: 5 1 5 2.5 3 8 8 9 10 The readings are: 5.0 1.0 5.0 2.5 3.0 8.0 8.0 9.0 10.0 The sum of row 1 is: 11.0 The sum of row 2 is: 13.5 The sum of row 3 is: 27.0 The sum of column 1 is: 15.5 The sum of column 2 is: 13.0 The sum of column 3 is: 23.0
再答： import java.util.Scanner; public class Sss { public static void main(String args[]) { double[][] array = new double[][] { { 1, 2, 3 }, { 4, 5, 6 }, { 7, 8, 9 } }; for (int row = 0; row < 3; row++) { for (int column = 0; column < 3; column++) { Scanner sc = new Scanner(System.in); try { array[row][column] = sc.nextDouble(); } catch (Exception e) { array[row][column] = 0.0; } } } double[] rowsum = new double[3]; double[] colsum = new double[3]; for (int i = 0; i < 3; i++) { for (int j = 0; j < 3; j++) { rowsum[i] += array[i][j]; colsum[j] += array[i][j]; System.out.print(array[i][j]+"\t"); } System.out.println(); } for (int i = 0; i < 3; i++) { System.out.println("The sum of row " + (i + 1) + " is: " + rowsum[i]); } for (int i = 0; i < 3; i++) { System.out.println("The sum of column " + (i + 1) + " is: " + colsum[i]); } } } ------------------------------------------------------- 你想要九个数字是输入的？