关于数学化简题,怎么从[1/(x+1)]*{(x-1)/(x+3)}+1]化简到[1/(x+1)]*[2(X+1)/(X
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/06/10 06:06:08
关于数学化简题,怎么从[1/(x+1)]*{(x-1)/(x+3)}+1]化简到[1/(x+1)]*[2(X+1)/(X+3)],
[1/(x+1)]*{(x-1)/(x+3)}+1]
=[1/(x+1)]*{ [(x-1)+(x+3)] /(x+3)}
=[1/(x+1)]*[2(X+1)/(X+3)]
再问: { [(x-1)+(x+3)] /(x+3)} 怎么等于[2(X+1)/(X+3)]
再答: 1/(x+1)]*{(x-1)/(x+3)+1} =1/(x+1)]*{(x-1)/(x+3)+(x+3)/(x+3)} =1/(x+1)]*{ [(x-1)+(x+3)] /(x+3)} =1/(x+1)]*{ [2x+2] /(x+3)} =1/(x+1)]*[2(X+1)/(X+3)] 你那个大括号应该位置错了,在最末尾
=[1/(x+1)]*{ [(x-1)+(x+3)] /(x+3)}
=[1/(x+1)]*[2(X+1)/(X+3)]
再问: { [(x-1)+(x+3)] /(x+3)} 怎么等于[2(X+1)/(X+3)]
再答: 1/(x+1)]*{(x-1)/(x+3)+1} =1/(x+1)]*{(x-1)/(x+3)+(x+3)/(x+3)} =1/(x+1)]*{ [(x-1)+(x+3)] /(x+3)} =1/(x+1)]*{ [2x+2] /(x+3)} =1/(x+1)]*[2(X+1)/(X+3)] 你那个大括号应该位置错了,在最末尾
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