求证在x=【0,π/2】时sin x,cos x,tan x,cot x 不会成等差数列
f(x)=|sin x+cos x+tan x+cot x+sec x+csc x|最小值
证明(tan^2x-cot^2x)/(sin^2x-cos^2x)=sec^2x+csc^2x
证明(tan^2x-cot^2x)/(sin^2x+cos^2x)=sec^2x+csc^2x
sin(x) cos(x) tan(x) cot(x) sec(x) csc(x) arcsin(x) arccos(x
化简sin(派-x)+sin(派+x)-cos(-x)+cos(2派-x)-tan(派+x)cot(派-x)
已知tan x=-3/4,求sin x ,cos x ,cot x 的值.
f(x)=|sin x+cos x+tan x+cot x+sec x+csc x|最小值答对马上采纳,
f(a)=[sin(π-x)cos(2π-x)tan(-x+3π/2)]/cot(-x -π)sin(-π--x) 化简
化简cos(π/2-x)cos(π/2+x)cot(π-x)/sin(3π/2+x)cos(3π+x)tan(π+x)
化简:sin(2派-x)tan(派+x)cot(-x-派)/tan(3派-x)cos(派-x)
已知函数f(x)=sin^2x+csc^2x+cos^2x+sec^2x+tan^2x+7cot^2x,x∈(0,π/4
请问sin(x+π/2)=?cos(x+π/2)=?tan(x+π/2)=?cot(x+π/2)=?sec(x+π/2)