In one model of the hydrogen atom,the electron revolves in a
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In one model of the hydrogen atom,the electron revolves in a circular orbit around the proton with a speed of 2.0106m/s.Determine the radius of the electron's orbit.
kQq/r²=mv²/r
k=9×10^9N·m²/C²
Q=q=1.6×10^-19C
m=9.1×10^-31kg
r=kQq/mv²(速度不对吧,那么慢的电子,怎么也该是它的几十万、上百万倍)
(先按2×10^6m/s算)= 6.3×10^-11m=63pm
k=9×10^9N·m²/C²
Q=q=1.6×10^-19C
m=9.1×10^-31kg
r=kQq/mv²(速度不对吧,那么慢的电子,怎么也该是它的几十万、上百万倍)
(先按2×10^6m/s算)= 6.3×10^-11m=63pm
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