求证:sin(a+b)cos(a-b)=sina*cosa+sinb*cosb
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求证:sin(a+b)cos(a-b)=sina*cosa+sinb*cosb
麻烦个位 帮个忙~
麻烦个位 帮个忙~
积化和差 sin(A)*cos(B) = (1/2)*[sin(A+B) + sin(A-B)]
2倍角公式 sin(2A) = 2*sinAcosA
sin(a+b)cos(a-b)
= (1/2)*{sin[(a+b)+(a-b)] + sin[(a+b)-(a-b)]}
= (1/2)*[sin(2a) + sin(2b)]
= (1/2)*[2*sin(a)*cos(a) + 2*sin(b)*cos(b)]
= sin(a)*cos(a) + sin(b)*cos(b)
2倍角公式 sin(2A) = 2*sinAcosA
sin(a+b)cos(a-b)
= (1/2)*{sin[(a+b)+(a-b)] + sin[(a+b)-(a-b)]}
= (1/2)*[sin(2a) + sin(2b)]
= (1/2)*[2*sin(a)*cos(a) + 2*sin(b)*cos(b)]
= sin(a)*cos(a) + sin(b)*cos(b)
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