几何数学题:如图在△ABC,∠BAD=∠CAD,AD=DB,DC⊥AC.求证:AB=2AC
如图,在三角形ABC中,∠BAD=∠CAD,AD=DB,DC垂直AC,求证AB =2AC
在△ABC中,AB=2AC,∠BAD=∠CAD,DA=DB,求证:DC⊥AC.
在△ABC中,∠BAD= ∠CAD,DA=DB,AB=2AC 求证:DC⊥AC
如图所示,在△ABC中,AB=2AC,∠BAD=∠CAD,AD=BD,求证:DC⊥AC
如图,在△ABC中,AD⊥BC,且AB+DC=AC+DB,求证AB=AC
如图,已知在△ABC中,AD平分∠BAC,求证DB/DC=AB/AC
已知:如图,△ABC是等腰三角形,AB=AC,AD是高,求证:BD=DC;∠BAD=∠CAD
已知如图在△ABC中,AB>AC,∠1=∠2.求证AB-AC>DB-DC
如图,在三角形ABC中,AB=AC,AD是高,求证1:AB=DC 2:角BAD=角CAD 要过
如图,△ABC中,AB=AC,AD是高,求证:∠BAD=∠CAD.
已知:如图,在三角形ABC中,BD=DC,若AD⊥AC,∠BAD=30°.求证:AC=½AB
已知如图在△ABC中,AB>AC,∠1=∠2,求证:AB-AC>DB-DC