L:x^2+y^2-2x-1=0正向,求∮[e^(x^2+y^2)dx+(2x^2+x)dy]/(x^2+y^2)
dy/dx,y=(1+x+x^2)e^x
x=sin(y/x)+e^2 求dy/dx
y=e^x/x^2+sin2x 求dy/dx
dy/dx-y/x=x^2
dy/dx=(e^x+x)(1+y^2)通解
求dy/dx=(x-y+5)/(x+y-2)
计算∫L(x^2-2y)dx+(x+y^2siny)dy,其中L是圆周x^2+y^2=2x的正向曲线,
dy/dx+(e^((y^2)+x))/y=0
求dy/dx y=e^(2x+1)
dy/ dx +2y=x*e^x的通解,
微分方程 dy/dx=(e^y+3x)/x^2
求微分方程的通解.[1+2e^(x/y)]dx+ 2e^(x/y)*[1-x/y]dy=0.