计算:[(x-2y)^+(x-2y)(x+2y)-2x(2x-y)]÷2x
有这样一道题:"计算(2*x*x*x-3*x*x*y-2*x*y*y)-(x*x*x-2*x*y*y+y*y*y)+【-
1、x(x-y)(x+y)-x(x+y)^2
计算:(x-y)^2*(y-x)^2*(x-y)^6
计算(x+y)(x+y)^2(-x-y)^3
计算:(-x-2y) * (3x-y)
计算:(x+y/x-y)÷(xy+x^2)
[(2x+y)(x-3y)+y(x+3y)]÷(2x)计算,
计算:(x-y)^7÷(y-x)^6+(-x-y)^3÷(x+y)^2
[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013
(1)(x^2/x)-y-x-y
[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y
【(x-y)^2+(x+y)(x-y)】除以 2x