∫x x² 2x 2dx
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用Γ函数做:Γ(t)=2∫x^(2t-1)×e^(-x^2)泊松积分Γ(1/2)=根下pai所以原式=根下pai/2
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原式=[3x(x−2)(x+2)(x−2)−x(x+2)(x+2)(x−2)]×(x+2)(x−2)2x=2x(x−4)(x+2)(x−2)×(x+2)(x−2)2x=x-4,当x=4−5时,原式=4
去分母得:2x=x-2+1,解得:x=-1,经检验x=-1是分式方程的解.
∵y=2xx2+1−3,∴(y+3)x2-2x+y+3=0当y≠-3时,∵x∈R,∴4-4(y+3)2≥0∴-4≤y<-3或-3<y≤2当y=-3时,x=0∴A=[-4,-2]…(4分)若k=0时,则
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方程左边1/(xx+x)+1/(xx+3x+2)+1/(xx+5x+6)+1/(xx+7x+12)+1/(xx+9x+20)对分母因式分解得1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(
由题意得,2-x≥0且x≠0,解得x≤2且x≠0.故答案为:x≤2且x≠0.
原式=SnX*Sn=1xX^2+2xX^3+…+nxX^(n+1)=Sn+1-(X+X^2+X^3+…+X^n+X^n+1)Sn+1-X*Sn=(X-X^n+2)/(1-X)Sn+1=Sn+(n+1)
xx+2xy-yy=-3两式相加即可
广义积分∫+∞1xe-x2dx=12∫+∞1e−x2dx2=−12e−x2|+∞1=−12limx→+∞e−x2+12e=12e故选:A.
2/9再问:过程,谢谢再答:由题目得y/x=2/3xy/xx+yy-yy/xx-yy=y/x-(y/x)²=2/3-4/9=2/9
原式=[(x²+y²-2y²)/y]/[(x-y)/xy]×1/(x²-y²)=[(x²-y²)/y]×[xy/(x-y)]×1/
xx+yy+4x-6y+13=0整理得:(x+2)^2+(y-3)^2=0那么只有(x+2)=0(y-3)=0x=-2y=3(x^2-2x)/(x^2+3y^2)=(4+4)/(4+3*9)=8/31
x^2+x-x^2-y=3x-y=3(x-y)^2=9x^2+y^2-2xy=9(x^2+y^2)/2-xy=9/2
令a=XX+YY则(a-2)a=3a²-2a-3=0(a-3)(a+1)=0a=3,a=-1因为XX+YY≥0所以XX+YY=3
x(x+1)-(xx+y)=-3x^2+x-x^2-y=-3x-y=-3(xx+yy)/2-xy=(x^2+y^2-2xy)/2=(x-y)^2/2=(-3)^2/2=9/2再问:是对的吧!再答:当然