y等于x方减4x加3有没有反函数?
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/03 03:33:02
(x-2)²+(y-3)²=1x=2+cosay=3+sinax²+y²=6sina+4cosa+14=√(6²+4²)sin(a+b)+1
已知x方加y方减2x加4y等于-5x方+y方-2x+4y+5=0x方-2x+1+y方+4y+4=0(x-1)方+(y+2)方=0所以x-1=0,y+2=0所以x=1,y=-2如果不懂,请追问,祝学习愉
X2-4X+Y2+6Y+13=0(X-2)2+(Y+3)2=0∴有X-2=0,X=2Y+3=0,Y=-3
14=1+4+9所以(x²-2x+1)+(y²+4y+4)+(z²+6z+9)=0(x-1)²+(y+2)²+(z+3)²=0平方大于等于0
x²+xy-2y²=0﹙x-y﹚﹙x+2y﹚=0x=y,x=-2y当x=y,﹙x²+3xy+y²﹚/﹙x²+y²﹚=﹙y²+3y&
√(x-4y)=4x-4y=4的2次方x-4y=16(1)(3x+5y)的3次方=-273x+5y=-3(2)(2)-(1)×3得3x+5y-3(x-4y)=-3-16×33x+5y-3x+12y=-
x=3x+20=4x-25先解x=3x+20-20=3x-x-20=2xx=-10再解3x+20=4x-2520+25=4x-3xx=45即方程x=3x+20=4x-25无解.
(x^2+5)/√(x^2+4)=√(x^2+4)+1/√(x^2+4)令t=√(x^2+4),则t≥2y=t+1/t单调递增,t=2时,ymin=5/2再问:那个x方加5怎么就等于根号x方加4加1再
再答:记得采纳哦
因为lnx递增所以y递增则真数递增-2x²+3x+4开口向下所以在对称轴x=3/4左边递增x02x²-3x-4
f(x)=4+3x-2x²在(-无穷,3/4)递增,根据同增异减,单调递增区间为(-无穷,3/4)
x+y=1(1).(x+y)(x-y)=9x-y=9(2)(1)+(2):2x=10x=5,(1)-(2):y=-4再问:能再详细点么(>﹏
x=2y=1
X^2+y^2=4求式=x^2-2√3-y^2=x^2-2√3-4+x^2=2x^2-2√3-4而x^2≤4则X^2=4时,原式最大为-2√3
x^2+y^2=4,设x=2cosa,y=2sina,则x^2-2√3xy-y^2=4(cosa)^2-8√3cosasina-4(sina)^2=4cos2a-4√3sin2a=8cos(2a+60
(x+y)/(x)=31+(y/x)=3得:y/x=2则:(x²+y²)/(x²-xy+y²)【分子分母同除以x²】=[1+(y/x)²]/
(x^2+y^2)*(x^2-1+y^2)-12=0可以设x^2+y^2=z那么有z(z-1)=12z^2-z-12=0(z-4)(z+3)=0z=4或z=-3但z是平方和一定大于0所以z=4记得采纳