y减x等于y除以x
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x/(y-x)
根据题意知:X/3=Y/4=Z/5设X/3=Y/4=Z/5=K则X=3K,Y=4K,Z=5K所以(X+Y)/(X-2Y+3Z)=(3K+4K)/(3K-2*4K+3*5K)=7K/(10K)=7/10
由x-y除以x+2y等于三分之一,得,(x-y)/(x+2y)=1/33(x-y)=x+2y3x-3y=x+2y,3x-x=2y+3y2x=5y解得x=5y/2所以求x-2y除以x+y=(x-2y)/
3X+XY-3Y/(X-XY-Y)?由1/X-1/Y=3得y-x=3xyx-y=-3xy则3X+XY-3Y/X-XY-Y化简为3(x-y)+xy/(x-y-xy)=3(-3xy)+xy/(-3xy-x
x=(m+1)/4,y=(m-1)/2m=4x-1,m=2y+14x-1=2y+1y=2x-1
由(2x-y)/(x+3y)=3(4x-2y)/(x+3y)-(4x+12y)/(2x-y)=2(2x-y)/(x+3y)-4(x+3y)/(2x-y)=2×3-4×1/3=14/3
2X-Y/X+Y=2X+Y/2X-Y=1/2原式=[2(2X-Y)/X+Y]-[4(X+Y)/2X-Y]=2*2-4*(1/2)=4-2=2P.S.第一次为团队答题,好鸡东哦o(∩_∩)o有什么不懂的
原题:x,y,z满足等式(3x+4y)/2=(6x+5y)/3=(4x-y+13z)/2,那么(x+2y+z)/(2x+3y-z)的值是多少由(3x+4y)/2=(6x+5y)/3求得y=3/2x=1
x、y互为倒数,则x与y有三个情况.1.当x>0时如:x=2,则y=1/2,所以x÷y=2÷(1/2)=4,所以x÷y=x²2.当x=0时则x÷y=0÷0=0,故没有意义,所以舍去3.当x<
是1/x+1/y=5么?题不对吧
x/(x+y)=zx=xz+yzx-xz=yzx(1-z)=yzx=yz/(1-z)
Y等于(565-19)÷(27-1)=21X等于565+21=586
用到求根公式再问:怎么解用一元二次方程公式法再答:再问:太给力了,你的回答完美解决了我的问题!
X比y3:2=300:200所以y=200因为5z=300z=60则X=180Y=120所以X-Y=180-120=60
[(x²-y²)²/(x+y)²]/(x-y)=[(x+y)(x-y)/(x+y)]²/(x-y)=(x-y)²/(x-y)=x-y如果不懂
x/y=8x-y=714联立,解得x=816,y=102
题目是不是(x^3+y^3)/(x+y)?应该等于x^2+xy+y^2