y=cos√x-e的-x两次方-搜答案-智慧作业帮

解题思路：考查三角恒等变换解题过程：varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/read

x^2+y^2=(x+y)^2-2xy=16-2xy=14=>xy=1=>x^4+y^4=(x^2+y^2)^2-2x^2y^2=196-2=194=>x^5+y^5=(x+y)(x^4-x^3y+x

1、x-y=3两边平方x²-2xy+y²=92xy=x²+y²-9=4所以xy=22、x²+y²=13两边平方x⁴+2x

方是哪个的方?xcos(x^2)的导数=cos(x^2)-2(x^2)sin(x^2)x*(cosx)^2=(cosx)^2+xsin(2x)(xcosx)^2=2(xcosx)(cosx-xsinx

(x-y)^5/[(y-x)^3(y-x)^2]＝(x-y)^5/[-(x-y)^3(x-y)^2]＝(x-y)^5/[-(x-y)^5]＝-1.

y'=4sin³xcosx-4cos³xsinx

y=sin^4x+cos^4x=(sin^2x)^2+(cos^2x)^2=(sin^2x)^2+2sin^2x*cos^2x+(cos^2x)^2-2sin^2x*cos^2x=(sin^2x+co

1.y的一次方与y的两次方互为相反数(1/5)x+1+(2x+1)/4=0答案自己算一下吧；2.9鸡蛋+5鸭蛋+3鹅蛋=10.7元2鸡蛋+6鸭蛋+8鹅蛋=5.8元=>11鸡蛋+11鸭蛋+11鹅蛋=16

负的（x-y）的10次方再问：为什么呢？我要过程麻烦你了再答：后面两个（y-x）可以提负号，二次的提出来是正的，三次的是负的。会了吧~

再问：求详解谢谢再答：

原式=[2x(x+y)-5x²]/[5x²(x+y)²]=(-3x²+2xy)/[5x²(x+y)²]=(-3x+2y)/[5x(x+y)&

dy=[-sin(√x)*1/2*x^(-1/2)-e^(-2x)*(-2)]dx=[1/2sin(√x)x^(-1/2)+2e^(-2x)]dx

X2-Y2=(X+Y)(X-Y)=8X-Y=4soX=4+Y(4+Y+Y)(4+Y-Y)=8(4+2Y)4=84+2Y=2Y=1soX=3

y=2cos²x-1+1+sin2x=sin2x+cos2x+1=√2(sin2x*√2/2+cos2x*√2/2)+1=√2(sin2xcosπ/4+cos2xsinπ/4)+1=√2si

利用格林公式：∮cP(x,y)dx+Q(x,y)dy=∫∫D(dQ/dx-dP/dy)dxdy首先需要构造封闭曲线.∫（x沿半圆周y=√2x-x^2从2积到0）（e^xsiny-y)dx+(e^xco

c

y=(sinx)^4+(cosx)^4=(sin²x+cos²x)²-2sin²xcos²x=1-(1/2)(2sinxcosx)²=1-s

f(-x)=(e^x-1)/(e^-x+1)=(e^2x-e^x)/(1+e^x)∴它是非奇非偶函数再问：就这样就好了？！不需要在分母分子乘以一个什么数在算下去吗。。搞不好还可以算下去呢...然后不是

=x^2+4xy+4y^2+y^2+6y+9=0(x+2y)^2+(y+3)^2=0x+2y=0,y+3=0x=6,y=-3x^2-y^2=6^2-(-3)^2=27

求y=cos方2X的周期

cos2x=cos方x-sin方x=2cos方x-1cos方2x=(cos4x+1)/2T=2兀/4=兀/2