y 1 3y=1 3(1-2x)

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x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x

是这样的:x^5+x^4=x^3(x^2+x)=(x^2+x)[(x^3-1)+1]=(x^2+x)(x^3-1)+x^2+x=[x(x+1)(x-1)](x^2+x+1)+x^2+x=(x^3-x)

1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550

1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550120x=550x=55/12=4.583

解方程(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=1

(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=(x/2)*(2/x(x+2))+(2/(x+2)(x+4))+.+2/(x+8)(x+10)=(x/2)*[1/x

f(x)=x/(x^2+1)

x/(x2+1)=(x-1)/xx3-2x2+x-1=0设y=x3-2x2+x-1y=x2(x-2)+x-2+1=(x-2)(x2+1)+1x增,y也增,所以y是单增函数,图像与x轴有交点,即f(x)

已知X=π/3,试求|X+1|-|X+2|+|X+3|-|X+4|.+|X+11|-|X+12|+|X+13|的值

去掉绝对值原式=x+1-x-2+x+3-x-4+x+5-x-6+x+7-x-8+x+9-x-10+x+11-x-12+x+13=x+13-6=x+7=π/3+7

y=(x^2+x)/(x+1)

这样算,分离变量:x²+x=(x+1)²-(x+1)然后,除下来,就等于x+1-1=x注意,x≠-1!

若x=π/3,|x+1|+|x+3|+...+|x+13|-|x+2|-|x+4|-...-|x+12|

每个绝对值里都是正数所以原式=x+1+x+3+x+5+……+x+13-x-2-x-4-x-6-……-x-12=x-1*6+13=x+7=π/2+7

2x-7/4x=13 3x+1/3x=20/21 x-0.28x=12.

1/4X=13X=5210/3X=20/21X=2/70.72X=12.96X=18

解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)

x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)

解方程((13x-x^2)/(x+1))(x+(13-x)/(x+1))=42

(X(13-X)(X+(13-X)))/(X+1)=42得分母是X^2(13-X)+(13-X)X分子是(X+1)再得分母X(13-X)(X+1)分子分母抵消的(X+1)X=42得X=6

x/x平方-x+2=2x/x+1

x/x(x-1)+2=2x/(x+1)1/(x-1)+2=2x/(x+1)x+1+2(x-1)(x+1)=2x(x-1)x+1+2x²-2-2x²-2x=0-x-1=0-x=1x=

解方程:x+1分之13x-x^2*(x+(x+1分之13-x))=42

(13x-x^2)/(x+1)*[x+(13-x)/(x+1)]=42设(13-x)/(x+1)=y.xy*(x+y)=426*7=42y=6x=1

求1/2x^2-1/4x+0.2x^3+0.25x-0.5x^2-1/5x^3+0.5x-1 其中x=12/13

1/2x^2-1/4x+0.2x^3+0.25x-0.5x^2-1/5x^3+0.5x-1=(1/2x^2-0.5x^2)+(0.25x-1/4x)+(0.2x^3-1/5x^3)+0.5x-1=0.

解方程:(1-3x)^2+(2x-1)^2=13(x-1)(x+1)

(1-3x)²+(2x-1)²=13(x-1)(x+1)1-6x+9x²+4x²-4x+1=13x²-13-10x+2=-1310x=15x=3/2

(13x-x^2)/(x+1)[x+(13-x)/(x+1)]=42

图片回答 请追问下再问:哦再答:

解方程:13x+8=11x -7x+2=2x-4 3x+2=-3+x x-3=-1/2x

 再问:看不清耶再答:我重拍再问:我采纳再答: 再答:不是说采纳的么再答:棒

x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002

=x^2002(x^4+x^3+x^2+x+1)=0提取公因式就行了

(x/x-1)+(5x-2)/x*x-x=1 求x(有图)

方程右边的1减到左边来,再同分得到(6x-2)/(x^2-x)=0得到x=1/3这个方程即使两边乘以x^2-x,x的最高次数为2次,也不会出现x^3,你肯定是什么地方弄错了

解不等式:7x^2+13x-2/(x+1)(x-2)>=0

(7x^2+13x-2)/(x+1)(x-2)>=0(7x-1)(x+2)/(x+1)(x-2)>=0(x+1)(x-2)≠0,x≠-1,x≠2原不等式等则于:(7x-1)(x+2)(x+1)(x-2