x的平方加2x减3除以sin(x 3)-搜答案-智慧作业帮

1楼最后算错了引用一下：1/(x+1)-1/(x²-1)÷(x+1)/(x²-2x+1)=1/(x+1)-1/(x+1)(x-1)×(x-1)(x-1)/(x+1)=1/(x+1)

你这样的叙述根本没有办法写出式子来

(81-x^4)/[(x^2+9)(x+3)]=(9-x^2)(9+x^2)/[(x^2+9)(x+3)]=(9-x^2)/(x+3)=(3-x)(3+x)/(x+3)=3-x

分子分母同除x^3,再问：这个我是同除以x的三次，后面是9x的平方-9x9除以x的平方2x3?有没有完整的解题过程?再答：lim((x+1)^3-(x-2)^3)/(x^2+2x+3)=lim(9x^

原式=(x-1)(x-2)/(x-2)(x-3)*(x-3)(x-4)/(x-1)(x-4)=1有疑问,请追问；若满意,请采纳,谢谢!

x平方减3x加1=0,x^2+1=3xx平方除以（x四次方加x平方加1）=x^2/(X^4+X^2+1)=X^2/{(X^2+1)^2-X^2}=X^2/{(3X)^2-X^2}=1/8

x2+xy-2y2=0(x-y)(x+2y)=0x-y=0,x+2y=0x=y或x=-2yx=y,则原式=(y2+3y2+y2)/(y2+y2)=5y2/2y2=5/2x=-2y,则原式=(4y2-6

先化简要求的式子,已知的等式左边将tan化成sin/cos,在化简试试,根据要求的式子来算,不要求tan,肯定有简便算法,我没算,看了看,你自己试试吧

lim{(x^2-2x+3)/(x^2+4x+5)](x→∞)=lim{(x^2-2x+3)/(x^2+4x+5)](x→∞)分子分母同除以x的平方(x^2)=lim{(1-2/x+3/x^2)/(1

因为x^2-x^2/2=3==>x^2=6==>x=根号61/(1-x)-(1/(1x))/(x/(x^2-1)x)=1/(1-x)-(1/(1x))/((xx^3-x)/(x^2-1))=1/(1-

你的题是[(x-2)/(x+2)]-1=3/(x^2-4)等式前面通分得：（x-2)/(x+2)-(x+2)/(x+2)=3/(x^2-4)化简：-4/(x+2)=3/(x^2-4)3x+6=-4x^

x的平方减2x加1除以x的平方减1的差加x减1除以x的平方加x的和减x原式=（x-1）²÷（x²-1）+（x-1）÷(x²+x)-x=(x-1)/(x+1)+（x-1)/

(3-2x²-4x)/(x²+2x-1)=-(2x²+4x-2-1)/(x²+2x-1)=-2+1/(x²+2x-1)=-2+1/[(x+1)

6x加2x的平方减3x加x平方加1=3x^2+3x+1,代入X＝－5时,其值＝61

(2x-4)/(3x²-12x+12)=2(x-2)/[3(x²-4x+4)]=2(x-2)/[3(x-2)²]=2/[3(x-2)]

当x不等于2/3时,结果是2x-1当x=2/3,无意义

(x^2-x-2)/(x+1)=(x-2)(x+1)/(x+1)=x-2

(4x^3-2x^2+x)/(3x^2+2x)=[x(4x^2-2x+1)]/[x(3x+2)]=(4x^2-2x+1)/(3x+2)公因式就是x

(x3-x2)\(x2+x-2)分母提出x2分子十字相乘=x2(x-1)\(x+2)(x-1)然后（x-1）约掉=x2\(x+2)