X的平方减4等于0的解
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(-5+根号41)/2再答:百分之百对,请采纳
121x²=25x²=25/121=(±5/11)²所以x=-5/11,x=5/11
x²+x-²=14
解题思路:利用一元二次方程根的判别式求解。解题过程:解:∵x2-2x+4=0∴△=(-2)2-4×1×4=4-16=-12<0∴此方程无解最终
x^2-x-4=0,即a=1,b=-1,c=-4,所以b^2-4ac=(-1)^2+16=17x的值为:[-b±√(b^2-4ac)]/2a=(1±√17)/2
X的平方减4X等于5x^2-4x-5=0(x-5)(x+1)=0x=5或x=-1
x^2+1/x^2=4x^2-2+1/x^2=4-2x^2-2*x*1/x+1/x^2=2(x-1/x)^2=2x-1/x=根号2或-根号2
4x^2-81=04X^2=81X^2=81/4X=±√(81/4)X=±9/2
4x^2-x-9=04x^2-x+1/16-1/16-9=0(2x-1/4)^2=9+1/16=144/162x-1/4=±四分之根号145x=二分之根号145加1x=负的二分之1减根号145希望能看
4x²-9=04x²=9x²=9/4x=±3/2
(x-3)²+4x(x-3)=0(x-3)[(x-3)+4x]=0(x-3)(5x-3)=0x1=3,x2=3/59(x-2)²=4(x+1)²3(x-2)=2(x+1)
将5移到左边x²-4x-5=0(x+1)(x-5)=0得两解x1=-1x2=5
x^2-4=0x^2=4x=±2
x^2-4x-5=0(x-5)(x+1)x=5或x=-1
6x²+3x-4x-2=06x²-x-2=0(3x-2)(2x+1)=0解得x=2/3,x=-1/2祝开心
5x^2-4x^2=88x^2=88x=±√88=±2√22
x²-x=0,及x(x-1)=0,所以x1=0,x2=1
(x-2)²-4(x+1)²=0平方差公式:[(x-2)+2(x+1)][(x-2)-2(x+1)]=03x(-x-4)=0x(x+4)=0x=0或x=-4