x的2次方减3x减10因式分解
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5m(x-y)²+10n(y-x)³=5m(x-y)²-10n(x-y)³=5(x-y)²[m-2n(x-y)]=5(x-y)²(m-2nx
(x-y)²+3(y-x)=(x-y)²-3(x-y)=(x-y)[(x-y)-3]=(x-y)(x-y-3)
x^4+x^3-2=x^4-x^3+2x^3-2=x^3(x-1)+2(x^3-1)=x^3(x-1)+2(x-1)(x^2+x+1)=(x-1)[x^3+2(x^2+x+1)]=(x-1)(x^3+
x^3-3x+2=x^3-3x+3-1=(x^3-1)-3(x-1)=(x-1)(x^2+x+1)-3(x-1)=(X-1)(x^2+x-2)=(x-1)^2(x+2)
楼主,题貌似错了吧,无法分解.我做过类似这道题可以分解的:x^4-2x3-27x2-44x+7用待定系数法就是要设原式=(x2+ax+1)(x2+bx+7)或=(x2+ax-1)(x2+bx-7)[因
x^3-3x+2=(x^3-1)-3x+3=(x-1)(x^2+x+1)-3(x-1)=(x-1)(x^2+x-2)=(x-1)^2(x+2)
-2X的平方+1
x^3-x=x(x^2-1)=x(x+1)(x-1)
x^3-x=x(x^2-1)=x(x+1)(x-1)
(x2+y2)(x+y)(x-y)
(x-1)(x+3)^2
x的3次方减4x的平方加4x=x(x²-4x+4)=x(x-2)²
1+x的5次方减x的3次方减x的2次方=(x^5-x³)-(x²-1)=x³(x²-1)-(x²-1)=(x³-1)(x²-1)=
利用a^3-b^3=(a-b)(a^2+ab+b^2)所以x^3-(1/2y)^3=(x-1/2y)(x^2+1/2xy+1/4y^2)
x³-2x²-x+2+x^5-2x^4=x^4(x-2)+x²(x-2)-(x-2)=(x-2)(x^4+x²-1)
4x4-4x3+x2=x2(4x2-4x+1)=x2(2x-1)2
xxx-xx-4=xxx-2xx+xx-4=xx(x-2)+(x-2)(x+2)=(x-2)(xx+x+2)
X^3-9x=x(x^2-9)=x(x+3)(x-3)