作业帮x平方-9/x平方+6x+9_等于
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/29 12:09:05
x平方+6x-9=x²+6x+9-18=（x+3）²-18=（x+3-3√2）（x+3+3√2）
原式=(x-3)^2)*[(x+3)/(x-3)(x-6)]=(x+3)(x-3)/(x-6)=(x^2-9)/(x-6)
根（x²-6x+9）+根（x²-4x+4）+根（x²-10x+25）=|x-3|+|x-2|+|x-5|；当x＜2时,x-3＜0,x-2＜0,x-5＜0.所以原式=3-x
（x^2-3x)/(x^4-6x^3+9x^2)=x(x-3)/[x^2(x-3)^2]=1/[x(x-3)]
格式有点乱,〖((1-x)/(3-x))^2/((x^2-6x+9)/(9-x^2 ))〗^ ×1/(x^2-2x+1)=〖((1-x)/(3-x))^2/(〖(X-3)〗^2/(
（3-x分之x-1）平方÷（x平方-6x+9分之9-x平方）平方*x平方-2x+1分之6+2x=[(x-1)/(3-x)]²÷[(9-x²)/(x²-6x+9)]
原式=（x-1)/(x-3)²-1/(x-3)+2x/(x+3)(x-3)=(x²+2x-3)/(x-3)²(x+3)-(x²-9)/(x-3)²(x
(x+3)=0x=-3
(X的平方+9x)/(x的平方+3x)+（x的平方-9)/(x的平方+6x+9)=x(x+9)/x(x+3)+(x+3)(x-3)/(x+3)²=(x+9)/(x+3)+(x-3)/(x+3
x的平方-6x+9/9-x的平方÷2x-6/x的平方+3x{(x-3)²/[(3-x)(3+x)]}÷{2(x-3)/[x(x+3)]}=[(3-x)/(3+x)]÷{2(x-3)/[x(x
原式=(x-3)/(x²+x)*1/(x-3)²约去x-3=1/[(x-3)(x²+x)]=1/(x³-2x²-3x)
1.(x²+x)/(x²-1)=x(x+1)/[(x+1)(x-1)]=x/(x-1)2.(x²-9)/(x²-6x+9)=(x+3)(x-3)/(x-3)&#
原式=(x+6)(x-3)/[x(x+6)]*1/(x-3)²=1/[x(x-3)]=1/(x²-3x)
(根号x平方-2x+1)+(根号x平方-4x+4)+(根号x平方+6x+9)=√﹙x-1)²+√﹙x-2)²+√(x+3)²=│x-1│+│x-2│+│x+3│
(x²+6x+9)分之(x-3)+(9-x²)分之x=(x²+6x+9)分之(x-3)-(x²-9)分之x=(x+3)²分之(x-3)-[(x+3)(
(4x+20)(x的平方-6x+9)/(3x-x的平方)(x的平方+2x-15)=4(x+5)(x-3)²/3（3-x）(x-3)(x+5)=-4/3
(x²-6x+9)/(x+1)÷(x²-9)/(x²+x)=[(x-3)²/(x+1)]×[x(x+1)/(x+3)(x-3)]=x(x-3)/(x+3)x的平
原式=x^2+9x/x^2+3x+x^2-9x/x^2+6x+9=2x^2+9x+9很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,
=(x+1)(x-1)/(x+3)²×[-1/(x-1)]×(x+3)/(x²+4)=-(x+1)/(x+3)(x²+4)
是+9原式=(x-3)²/x(x-3)*x(x-5)/(x-5)(x-6)-1=(x-3)/(x-6)-1=(x-3-x+6)/(x-6)=-3/(x-6)