x平方-3xy-10y平方因式分解-搜答案-智慧作业帮

X平方+2XY+Y平方-2X-2y-3=(x+y)^2-2(x+y)-3=(x+y-3)(x+y+1)

原式=(x+y)(x-y)/(x-y)^2=(x+y)/(x-y)=120/100=1.2^2指平方

（x-y）（x-y-2）-3

答：-x³y+2x²y-xy=-xy(x²-2x+1)=-xy(x-1)²

3x(x^2-2)y^2+6xy^2+9x^2y^2再问：O(∩_∩)O谢谢再答：原式=3x^3-6x^2y+3xy^2提取公因式，得3x(x^2-2xy+y^2)由完全平方公式，得3x(x-y)^2

原式=-y(4x²-4xy+y²)=-y(2x-y)²

1）—（x+y）四次方2）（3x+y）（3x-y+2）3）（x-3）（7x+y）4）（1+x-2y）（1-x+2y）5）5（y-x）平方（1-2y+x）6）6（a-b）平方（a-2b）7）（x+y-2

2x^2-10x=2x(x-5)x^3y-2x^2y^2+xy^3=xy(x^2-2xy+y^2)=xy(x-y)^2x^2+x-2=(x+2)(x-1)x^2-4x-12=(x-6)(x+2)x^3

xy(x-y)-x(x-y)平方=(x-y)[xy-x(x-y)]=(x-y)[2xy-x^2]=(x-y)*x(2x-y)-a平方+1.9b平方=(b根号1.9+a)(b根号1.9-a)-12xy+

x²-4xy+3y²-4x+10y+3=(x-y)(x-3y)-4x+10y+3=(x-y-3)(x-3y-1)x²+xy-2y²+2x+7x-3=(x+2y)

双十字相乘.

1x²+2xy-3y²=x²+2xy+y²-4y²=（x+y）²-(2y)²=(x+y+2y)(x+y-2y)=(x+3y)(x-

=7x²-4x²+4xy-y²=7x²-(2x-y)²=(√7x+2x-y)(√7x-2x+y)本题答案不唯一的

原式=（x-y)²-10(x-y)+16=(x-y-2)(x-y-8)原式=(2x-y)(x+2y)-x+8y-62x-y3×x+2y-2x和y系数符合所以原式=(2x-y+3)(x+2y-

1）2x²+3x-6有两种方法（1）求根法对于关于x的方程ax²+bx+c=0,若x1,x2是其两根那么ax²+bx+c=a(x-x1)(x-x2)设2x²+3

x平方-2xy-3y平方+3x-5y+2=(x²-2xy-3y²)+(2x-6y)+(x+y)+2=(x-3y)(x+y)+2(x-3y)+(x+y)+2=(x-3y)(x+y+2

x^2-3xy+2y^2=(x-2y)(x-y)

=（x-y）（x-2y）

原式=(x+y)(x+2y)+2(x+2y)=(x+2y)(x+y+2)希望我的回答能帮助到您,

-3x的平方+6xy-3y的平方=-3(x²-2xy+y²)=-3(x-y)²请点击下面的【选为满意回答】按钮,