X四次方减6X加5等于0
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∵x²-3x+1=0∴x²+1=3x(x²+1)×1/x=3x×1/x∴x+(1/x)=3∴[x+(1/x)]²=3²x²+2×x×1/x+
x^2-3x+1=0x-3+1/x=0x+1/x=3(x+1/x)^2=9x^2+2+1/x^2=9x^2+1/x^2=7(x^2+1/x^2)^2=49x^4+2+1/x^4=49x^4+1/x^4
x^2-13x+1=0.x≠0.x-13+1/x=0,x+1/x=13.(x+1/x)^2=169x^2+1/x^2=169-2=167(x^2+1/x^2)^2=167^2.x^4+1/^4=167
X²+2X-1=0两边同时除以x得x+2-1/x=0x-1/x=-2两边同时平方得x²+1/x²=6两边同时平方得x4+1/x4=34
x^2-5x+1=0方程两边同除以xx-5+1/x=0x+1/x=5(x^4+1)/x^2=x^2+1/x^2=(x+1/x)^2-2=5^2-2=25-2=23
x²-3x+1=0得x=(3±√5)/21/x=(3-√5)/2或(3+√5)/2x+1/x=3x^4+1/x^4=(x²+1/x²)²-2=[(x+1/x)&
x⁴+2x³+6x²+5x-14=(x⁴+2x³)+(6x²+5x-14)=x³(x+2)+(6x-7)(x+2)=(x+2)
x^2-13x+1=0x1=[13+√(13*13-4)]/2=6.5+0.5√165x2=6.5-0.5√165当x=x1时x^2=6.5x6.5+165/4+6.5√165=(169+165)/4
你确定你没抄错题吗?
X^2+X^-2=3则:(X^2+X^-2)^2=9得到X^4+2+X^-4=9解得X^4+X^-4=7注:X^-2为X的-2次方,X^2为X的平方.望采纳
x^2-3x+1=0x^2=3x-1x^4=(3x-1)^2=9x^2-6x+1x^4-7x^2+1=9x^2-6x+1-7x^2+1=2x^2-6x+2=2(x^2-3x+1)=0
x^2-5x+1=0显然x不是0,两边除以x有x-5+1/x=0也就是x+1/x=5所以x^2+1/(x^2)=(x+1/x)^2-2=23x^4+1/(x^4)=(x^2+1/(x^2))^2-2=
由x^2-5x+1=0两边同除以x得x+1/x=5(x^4+1)/x^2=x^2+1/x^2=(x+1/x)^2-2=5^2-2=23
(x-2)^4=ax^4+bx^3+cx^2+dx+e令x=1则a+b+c+d+e=a*1^4+b*1^3+c*1^2+d*1+e=(1-2)^4=1令x=-1则a-b+c-d+e=a*(-1)^4+
解x^4-7x²+6=0令t=x²≥0则t²-7t+6=0(t-6)(t-1)=0∴t=6,t=1∴x²=6,或x²=1∴x=√6,或x=-√6,或x
再问:x²(x+2)=1能求出吗?再答:-1再问:我查了,4个解
x²-4x+1=0两边同时除以xx-4+1/x=0x+1/x=4两边同时平方x²+2+1/x²=16x²+1/x²=14两边同时平方x^4+2+1/x
x^2/(x^4+1)=33x^4+3=x^2两边平方9x^8+18x^4+9=x^4两边减去9x^49x^8+9x^4+9=-8x^4所以x^4/(x^8+x^4+1)=-9/8再问:标准答案是:1
x-1/x=3两边平方得:x²-2+1/x²=3²x²+1/x²=9+2x²+1/x²=11两边平方得:x^4+1/x^4+2=1
您好:x+1/x=5(x+1/x)平方=5平方x平方+2+1/x平方=25x平方+1/x平方=23(x平方+1/x平方)平方=23平方x的4次方+2+1/x的4次方=529x的4次方+1/x的4次方=