x÷2 x÷4=1.5

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(1+2x-4/x²-x-2)÷x+3/x²-1 先化简再求值 X=根号3

1+(2x-4)/(x^2-a-2)]/[(x+3)/(x^2-1)]={1+2(x-2)/[(x-2)(x+1)]}(x^2-1)/(x+3)=[1+2/(x+1)](x+1)(x-1)/(x+3)

(x+1)(x²-x+1)+6x³÷(-2x²)+(-x^6)÷x^4,其中x=-2

(x+1)(x²-x+1)+6x³÷(-2x²)+(-x^6)÷x^4,=x³+1-3x-x^2,=x^3-x^2-3x+1=-8-4+6+1=-5

(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3

(x+1-1/1-x)÷(x-x²/x-1)=[(x+1)+1/(x-1)]×[-(x-1)/x(x-1)]=(x²-1+1)/(x-1)×(-1/x)=-x/(x-1)(x-4/

15X÷2=60 4X+X=3.15 3.4X+1.8=8.6 5X-X=2.4 1.5X-X=1 6.6X-6X=1.

①15X÷2=60        15X×12=60     &nbs

先化解,在求值;(3x/x-1-x/x+1)÷x四次方-4x²/x³-x,其中x=根号2+2

原式=(3x²+3x-x²+x)/(x+1)(x-1)*x(x²-1)/x²(x²-4)=(2x²+4x)/(x+1)(x-1)*(x+1)

化简:(x+2分之2x-x-2分之x)÷x²-4分之x的结果=?

(x+2分之2x-x-2分之x)÷x²-4分之x(x+2x/2-x-x/2)÷x²-x/4=x/2÷x²-x/4=1/2x-x/4很高兴为您解答,祝你学习进步!有不明白的

先化简再求值:(x+2/x²-2x - x-1/x²-4x+4)÷ x-4/x,其中x=3/2

(x+2/x²-2x-x-1/x²-4x+4)÷x-4/x={(x+2)(x-2)/[x(x-2)²]-x(x-1)/[x(x-2)²]}·x/(x-4)={(

已知(x-根号2+1)(x-2)=0,求代数式[(x-1)/(x-3)-(x-4)/x]÷(x^2+x-6)/(x^2+

注意:本题x=2时题目没意义,应该舍去(这是很多学生错误所在)这里x只能取根号2-1  

2x^2-4x/x+2`x^2+2x/x^2-4x+4÷x/3x-6,其中x=根号3/2

原式=2x(x-2)/(x+2)×x(x+2)/(x-2)²×3(x-2)/x=6x当x=√3/2时原式=3√3

化简求值 (x³+4x²)÷x+(2x+1)(2x-1)-4x(x+1) x=-2

原式=x^2+4x+4x^2-1-4x^2-4x=x^2-1代入x=-2原式=3

已知(x+根号二)/(x-2)÷(x²+4x+4)/(x²-4),其中x满足(x-2)(x+3)=0

(x-2)(x+3)=0x=2(舍去),x=-3(x+根号二)/(x-2)÷(x²+4x+4)/(x²-4)=(x+根号二)/(x-2)÷(x+2)²/(x+2)(x-2

先化简再求值:x^3-2x^2+4x/x^2-4x+4÷x^2-2x+4/x-2,其中x=4

x^3-2x^2+4x/x^2-4x+4÷x^2-2x+4/x-2=x(x²-2x+4)/(x-2)²÷(x-2)/(x²-2x+4)=x(x²-2x+4)/(

已知x=√2+1,求(x²+x-6)/(3-x)×(2x-6)/(x²-4x+4)÷(x+3)

分子分母可以化简的,十字相乘法学过吗?

先化简,再求值 2x-6/4-4x+x^2÷x-3/x-2,其中x=-1

2x-6/4-4x+x^2÷x-3/x-2=-2x-7/2+x-3/x=-x-3/x-7/2=1+3-7/21/2

0.3+0.3x=0.39 x= 2x-1.5x=7.6x x= 0.36x÷0.3=1.2 x=

0.3+0.3x=0.39x=0.32x-1.5x=7.6xx=00.36x÷0.3=1.2x=16(x+1.2)=18.6x=1.97x+2x=8.1x=0.9(x-5)÷3=1.7x=10.15(

先化简,再求值(2x-6)/(4-4x+x^2)÷ (x+3)× (x^2+x-6)/(3-x),其中x=-1/2

原式=2(x-3)/(x-2)²×1/(x+3)×(x-2)(x+3)/[-(x-3)]=-2/(x-2)当x=-1/2时原式=-2/(-5/2)=4/5

已知x^2-3x=2x+14求(4x^3-6x^2+2x)÷(2x)-(x+1)^2+1的值

x²-3x=2x+14x²-5x=14∴﹙4x³-6x²+2x﹚/2x-﹙x+1﹚²+1=2x²-3x+1-x²-2x-1+1=x

x(2-1/x)+x/(x^2-2x)÷(3-x)/(x^2-4)

x(2-1/x)+x/(x^2-2x)÷(3-x)/(x^2-4)=x((2x-1)/x)+x/(x^2-2x)x(x^2-4)/(3-x)=(2x-1)+(x+2)/(3-x)=(7x-3-2x^2

x-2/(x^2-9)(1+(2x-7/x^2-4x+4)÷(x+1)/(x+3)其中x=2010

=(x-2)/(x+3)(x-3)×(x²+2x-3)/(x-2)²×(x+3)/(x+1)=(x-2)/(x+3)(x-3)×(x-3)(x+1)/(x-2)²×(x+