x²-y²-4x 6y-5分解因式

x²-4y²+x-2y=(x²-4y²)+(x-2y)=(x-2y)(x+2y)+(x-2y)=(x-2y)(x+2y+1)很高兴为您解答,祝你学习进步!【学习

解法一用双十字相乘法分解x^2-2xy-8y^2-x-14y-6=(x^2-2xy-8y^2)-x-14y-6=(x-4y)(x+2y)-(x+14y)-6=[(x-4y)-3][(x+2y)+2]=

3x^2+5xy-2y^2+x+9y-4=(3x-y)(x+2y)+4x+8y-3x+y-4={(3x-y)+4}(x+2y)-3x+y-4=(3x-y+4)(x+2y-1)

2x^2+xy-y^2-4x+5y-6=(2x-y)(x+y)-4x+5y-6=(2x-y)(x+y)+(2x+2y)-6x+3y-6=(2x-y)(x+y)+2(x+y)-6x+3y-6=(x+y)

原式=x²-Y²-x-5y-6=(x²-x+1/4)-(Y²+5y+25/4)=(x-1/2)²-（Y+5/2)²=[(x-1/2)+(Y+

2x^2+xy-y^2-4x+5y-6=(2x-y)(x+y)-4x+5y-6=(2x-y)(x+y)+(2x+2y)-6x+3y-6=(2x-y)(x+y)+2(x+y)-6x+3y-6=(x+y)

x^2-x-4y^2+2y=(x^2-4y^2)-(x-2y)=(x+2y)(x-2y)-(x-2y)=(x-2y)(x+2y-1)

你是说分成两个括号还是就是最简单的分解因式啊?最简单的就是：X（X-5）两个括号的就是：（X-根号5）（X-根号5）

x^2+3xy+2y^2+4x+5y+3=(x+y)(x+2y)+3(x+y)+(x+2y)+3=(x+y)(x+2y+3)+(x+2y+3)=(x+y+1)(x+2y+3)

原式=2(x+y)²-5(x+y)-3=[2(x+y)+1][(x+y)-3]=(2x+2y+1)(x+y-3)

1.原式=（3x+4y）[3x+4y-3x]/(-4y)=(3x+4y)[4y]/(-4y)=-(3x+4y)=-3x-4y2.原式=[(3a-3b)-(2a+2b)][(3a-3b)+(2a+2b)

3x²+5xy-2y²+x+9y-4=(3x-y)(x+2y)+x+9y-4=(3x-y+4)(x+2y-1)用二次十字相乘法：(1)3x²+5xy-2y²=(

(x+2y)(x-2y)-(x-4y)(x+4y)+(6y-5x)(6x-5y)=x^2-4y^2-x^2+16y^2+36xy-30y^2-30x^2+25xy=-18y^2+61xy-30x^2

(x+y)^4+(x+y)^2-20＝[﹙x＋y﹚²＋5﹚][﹙x＋y﹚²－4]＝﹙x²＋2xy＋y²＋5﹚﹙x＋y－2﹚﹙x＋y＋2﹚

x^2+2xy+y^2-4x-4y-5=（x+y）²-4（x+y）-5=（x+y）²-4（x+y）+4-9=（x+y-2）²-9=（x+y-2）²-3²

解题思路：先用十字相乘法、再运用平方差公式可解。解题过程：同学：另两道题目，我一时间没能解答出来，请你再检查一下原题。很抱歉，请你原谅！

原式=(x+y)(x-y)+5x+3y+4x+y1×x-y4x系数1+4=5y系数-1+4=3所以原式=(x+y+1)(x-y+4)

2X^2+xy-Y^2-4x+5Y-6=(2x-Y)(x+Y)-4x+5y-6=(2x-Y+a)(x+y+b)恒成立,可解得a=2,b=-3.所以2X^2+xy-Y^2-4x+5Y-6=(2x-Y+2

题目有误,应为分解因式：2x方+xy-y方-4x+3y-6=(2x-y-2)(x+y-3)十字相乘法2-1-211-3

4x^4y^2-5x^2y^2-9y^2=y^2(4x^4-5x^2-9)=y^2(4x^2-9)(x^2+1)=y^2(2x-3)(2x+3)(x^2+1)