x²+2x+y²-6+10=0

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已知4x^2+y^2-4x-6y+10=0,求(2\3x根号9x+y^2根号x/y^3)-(x^2-5x根号y\x) 拜

4X^2+Y^2-4X-6Y+10=0(4X^2-4X+1)+(Y^2-6Y+9)=0(2X-1)^2+(Y-3)^2=0平方大于等于0,相加等于0,若有一个大于0,则另一个小于0,不成立所以两个都等

7.X*X+2X+Y*Y-6Y+10=0,则xy=?

7.x*x+2*x+y*y-6y+10=(x+1)*(x+1)+(y-3)*(y-3)=0x+1=0且y-3=0所以x*y=-38.再加个4*x就好了11.原式=(x-2)*(x-2)+(y+3)*(

x^2+6x+y^2+4x+10=0,则x+y等于多少?

好吧题目应该是x^2+6x+y^2+4y+10=0解体是配方了把10分成1+9配成(x+3)^2+(y+1)^2=0平方大于等于0所以x+3=0,y+1=0,嗯x+y=-4了,希望可以帮到你.

已知X,Y,满足(X+3Y)(X-3Y)=-10(Y^2-6/5)和2X(Y-1)+4(1/2X-1)=0

很多数学符号,还是写出来方便.

先化简,在求值;2(x-y)^2+(x+y)(x-y),其中x^2+y^2-6x+2y+10=0

(x²-6x+9)+(y²+2y+1)=0(x-3)²+(y+1)²=0所以x=3,y=-1原式=2x²-4xy+2y²+x²-y

x²-2x+y²+6y+10=0,求—9(x+y)²+(3x-2y)(2y+3x)的值

由x²-2x+y²+6y+10=0得,(x-1)²+(y+3)²=0则x=1,y=-3—9(x+y)²+(3x-2y)(2y+3x)=-9*(-2)&

已知:x²y²-2x+6y+10=0则x+y=

x²-2x+y²+6y+10=0x²-2x+1+y²+6y+9=0(x-1)²+(y+3)²=0x-1=0y+3=0∴x=1y=-3∴x+y

已知x^2+2x+y^2-6y+10=0 求(x+y)^2

x^2+2x+y^2-6y+10=0(x+1)²+(y-3)²=0∴x=-1,y=3(x+y)²=(-1+3)²=4

-8(2x-y)-{7x-[6x+2y-(10x-8y)]}

-8(2x-y)-{7x-[6x+2y-(10x-8y)]}=-16x+8y-[7x-(6x+2y-10x+8y)]=-16x+8y-(7x-6x-2y+10x-8y)=-16x+8y-7x+6x+2

已知x^2+y^2--6x--2y+10=0,求x+y/x--y

x^2+y^2-6x-2y+10=0x^2-6x+9+y^2-2y+1=0(x-3)^2+(y-1)^2=0x=3,y=1(x+y)/(x-y)=4/2=2

x方-2x+y方+6y+10=0 求x,y

原式=x^2-2x+1+y^2+6y+9=0=(x-1)^2+(y+3)^2=0∴x=1,y=-3不懂再问

X^2+y^2-2x+6y+10=0,求x+y的值

x²-2x+y²+6y+10=0x²-2x+1+y²+6y+9=0(x-1)²+(y+3)²=0x-1=0y+3=0∴x=1y=-3∴x+y

已知x^2-2x+y^2+6y+10=0,求分式x-y/x+y的值

x^2-2x+y^2+6y+10=0(x-1)^2+(y+3)^2=0x=1y=-3(x-y)/(x+y)=4/(-2)=-2

x²-2x+y²+6y+10=0,则x+y=?

x方+2x+y方-6y+10=0x²+2x+1+y²-6y+9=0(x+1)²+(y-3)²=0所以(x+1)²=0,(y-3)²=0x+1

已知x的平方+2x+6x+10=0,则x+y等于多少

x^2+2x+y^2+6y+10=0x^2+2x+1+y^2+6y+9=0(x+1)^2+(y+3)^2=0(x+1)^2=0,(y+3)^2=0x=-1,y=-3x+y=-1-3=-4

已知:4x^2+y^2-4x-6y+10=0,求y/x-x/y的值

4x^2+y-4x-6y+10=0(2x-1)^2+(y-3)^2=0x=1/2y=3y/x-x/y=6-1/6=35/6