作业帮x² xy-2y²因式分解
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/12 04:16:01
(x+1)(y+1)
x^2-2xy+y^2+x-y=(x-y)^2+(x-y)=(x-y)(x-y+1)
8（x平方-2y平方)-x(7x+y)+xy=8x平方-16y平方-7x平方-xy+xy=x平方-4y平方=(x-2y)(x+2y)手机提问的朋友在客户端右上角评价点【满意】即可.再问：太棒了！连我这
解题思路：本题主要利用完全平方公式进行因式分解即可求出结果解题过程：解:x²－6xy＋9y²=(x-3y)2
x^2-2xy-3y^2+x+y=x*x-2*x*y-3*y*y+x+y=(x-3y)(x+y)+(x+y)=(x+y)(x-3y+1)如果是初中生,分解到这里就可以了如果是高二及以上,可能要在复数范
x²＋y－xy－x＝﹙x²－xy﹚＋﹙y－x﹚＝x﹙x－y﹚－﹙x－y﹚＝﹙x－y﹚﹙x－1﹚
题目不清楚啊,那个是几次方啊?算了,我就按2次方做了啊2x^2+xy-6y^2=(2x-3y)(x+2y)6（x+y)^2-5(x+y)-1=[6(x+y)+1][(x+y)-1]=(6x+6y+1)
题目是不是x^2y-7xy+6yx^2y-7xy+6y=y(x^2-7x+6)=y(x-1)(x-6)
题目应是x^2+xy-2y^2-x+7y-6=(x^2-xy+2x)+(2xy-2y^2+4y)-(3x-3y+6)=x(x-y+2)+2y(x-y+2)-3(x-y+2)=(x-y+2)(x+2y-
xy+2x+y+2=y(x+1)+2(x+1)=(x+1)(y+2)
1-x-y+xy=(1-x)-(y-xy)=(1-x)-y(1-x)=(1-x)(1-y)
因式分解xy²-2xy+x+2y-1解xy²-2xy-y²+x+2y-1=xy²-2xy+x-y²+2y-1=x(y²-2y+1)-(y&#
x^2y+xy^2=xy(x+y)
xy-x-y+1=x(y-1)-y+1=x(y-1)-(y-1)=(y-1)(x-1)
(x+y)(x-y)-x(y+1)-y(y+1)=(x+y)(x-y)-(x+y)(y+1)=(x+y)(x-2y-1)
xy+y平方+x-y-2=xy+x+y^2-y-2=x(y+1)+(y+1)(y-2)=(y+1)(x+y-2)
y^3+xy^2+2xy+x^2-1=(x+y-1)(x+y^2+y+1)再问：烦写出过程再答：
-x^2+2xy-y^2=-（x²-2xy+y²)=-(x-y)²
(x-1)(y-1)
xy-x-y+1=x(y-1)-(y-1)=(x-1)(y-1)(xy-x-y+1)^2=(x-1)^2(y-1)^2