x^2 y^2 z^2-4z=0的二阶偏导数怎么求

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2x+3y-4z=0.,3x+4y+5z=0,则x+y+z/x-y+z详细的解题过程

3x+4y+5z=0(1)2x+3y-4z=0(2)(1)-(2)x+y+9z=0(3)x+y=-9z(2)-2*(3)y-22z=0y=22z代入(3)解得x=-31zx-y=-53z(x+y+z)

已知x/2=y/3=z/4,且x+y+z不等于0,求2x+3y-4z/x+y+z的值

x/2=y/3=z/4=kx=2k,y=3k,z=4k2x+3y-4z/x+y+z=(4k+9k-16k)/(2k+3k+4k)=-1/3再问:确定?

已知x、y、z满足方程组:x+y-z=6;y+z-x=2;z+x-y=0 求x、y、z的值

x+y-z=6y+z-x=2z+x-y=0三式相加得x+y+z=8-得2z=2z=1-得2x=6x=3-得2y=8y=4x=3y=4z=1

已知{3x+4y+5z=0,2x+3y-4z=0,求x+y+z/x-y+z的值.

哇,这个很复杂啊再问:你会吗?

已知2x+3y-4z=0,3x+4y+5z=0,求x+y+z/(除以)x-y+z的值.

将Z当成已知数,将X、y用Z来表示2x+3y-4z=03x+4y+5z=0整理得:2x+3y=4z3x+4y=-5z变成二元二次方程解之得:x=-31zy=22z代人x+y+z/x-y+z=2/13

已知2x+3y-4z=0,3x+4y+5z=0,求x+y+z/x-y+z的值.

2x+3y=4z(A式),3x+4y=-5z(B式)A*3-B*2:y=22zA*4-B*3:x=-31z(x+y+z)/(x-y+z)=(-31z+22z+z)/(-31z-22z+z)=2/13

已知:2X-3y+2z=0,x+4Y-9/2z=0求:X:Z的值.X:y:Z的值.X+2y+X/X+y+Z的值. 已知:

1、x+4y-9/2z=0即2x+8y-9z=0(1)2x-3y+2z=0(2)(1)-(2)11y-11z=0y=z(1)×2+(2)×94x+16y-18z+18x-27y+18z=022x-11

已知x+4y+3z=3x-2y-5z=0,求x+2y-z/2x-3y+7z的值

x+4y+3z=3x-2y-5z=0则x+4y+3z=0①3x-2y-5z=0,则6x-4y-10z=0②①②两式相加,得7x-7z=0,所以x=z代入①,得z+4y+3z=0,所以y=-z所以x+2

已知2x+2y-4z=0,2x+4y+5z=0,求x+y+z/x-y+z的值

本题不一定要算出x、y,也能解出.(1)2x+2y-4z=0(2)2x+4y+5z=0(2)-(1):2y+9z=0即2y=-9z(1)÷2可得:x+y=2z故x+y+z=3z则x-y+z=(x+y+

4x-3y-6z=0,x+2y-7z=0是一个方程组,那么x-y+z/x+y+z的值等于

1/3再问:过程再答:4x-3y-6z=0(1)x+2y-7z=0(2)(2)×4-(1)得11y-22z=0即y=2z(3)(1)×2+(2)×3得11x-33z=0即x=3z(4)将(3)、(4)

1.已知x,y,z满足2│x-y│+(根号2y-z)+z平方-z+(1/4)=0,求x,y,z值.

1.z²-z+1/4=(z-1/2)².绝对值、根号、平方数都是非负的,而相加为0.所以都为0.即x=y,2y=z,z=1/2.所以x=y=1/4,z=1/2.2.2002x200

若z≠0,且4x=7y+5z,2x+y=z,求x,y,z的值

我的补充2011-12-1321:144x=7y+5z2x=z-y即4x=2z-2y所以7y+5z=2z-2y3z=-9yy=-1/3z将结果带入第一个等式x=-2/3z就得到x:y:z=2:1:-3

已知x平方+ y平方+z平方减2z+4y+6z+14=0,求x+y+z的直

即(x²-2x+1)+(y²+4y+4)+(z²+6z+9)=0(x-1)²+(y+2)²+(z+3)²=0平方相加则都等于0所以x-1=0

已知4x-3y+z=0,x+2y-8z=0,xyz不等于0,求x+y-z/x-y+2z的值

4x-3y+z=0(1)x+2y-8z=0(2)(1)-(2)×4得-11y+33z=0∴y=3z把y=3z代入(2)得x=2z把x=2z,y=3z代入x+y-z/x-y+2z得原式=(2z+3z-z

已知x.y.z满足方程组x+2y-4z=0 2x+y-5z=0 求x:y:z的值

x+2y-4z=0①2x+y-5z=0②①*2-②:y=z③③代入①:x=2zx:y:z=2:1:1

已知x²+y²+z²-2x+4y-6z+14=0,求x+y-z/x+y+z的值

x^2+y^2+z^2-2x+4y-6z+14=0x^2-2x+1+y^2+4y+4+z^2-6z+9=0(x-1)^2+(y+2)^2+(z-3)^2=0x=1,y=-2,z=3x+y-z=1-2-

x*x+y*y+2z*z-2x+4y+4z+7=0,求xyz的值

x*x+y*y+2z*z-2x+4y+4z+7=0(x*x-2x+1)+(y*y+4y+4)+2(z*z+2z+1)=0(x-1)^2+(y+2)^2+2(z+1)^2=0x=1,y=-2,z=-1x

若x/2=y/3=z/4不等于0,求x+y+z/x+y-z的值

令a=x/2=y/3=z/4则x=2a,y=3a,z=4a所以原式=(2a+3a+4a)/(2a+3a-4a)=9a/a=9

2x+3y-4z=0,3x+4y+5z=0,求x+y-z/x-y+z的值

2x+3y-4z=0,3x+4y+5z=0两式把z看作已知,可解得x=-31zy=22z(x+y-z)/(x-y+z)=(-31z+22z-z)/(-31z-22z+z)=5/26