xy²-2xy 2y-4

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因式分解xy²-2xy+2y-4

xy²-2xy+2y-4=xy(y-2)+2(y-2)=(y-2)(xy+2)

先化简,再求值 ⒈2(Xy+Xy)-3(Xy-xy)-4Xy,其中X=1,y=-1

1.2(Xy+Xy)-3(Xy-xy)-4Xy=2*2xy-0-4xy=4xy-4xy=02.1/2ab-5aC-(3acb)+(3aC-4aC)=1/2ab-5ac-3acb-ac=1/2ab-6a

[(xy+2)(xy-2)-2x^2y^2+4]/xy,其中x=10,y=-1/25

[(xy+2)(xy-2)-2x2y2+4]÷(xy)=(x2y2-4-2x2y2+4)÷xy=-x2y2÷xy=-xy,当x=10,y=1/25时,原式=-2/5.

[(xy+2)(xy-2)-2x^2y^2+4]/(xy),其中:x=10,y=-1/25

[(xy+2)(xy-2)-2x^2y^2+4]/(xy)=[(x^2y^2-4)-2x^2y^2+4]/(xy)=-x^2y^2/xy=-xy=-10*(-1/25)=2/5

xy^2-4x 因式分解

xy^2-4x=x(y+2)(y-2)-2a^2+4ab-2b^2=-(a-b)^2a^2(x-y)+b^2(y-x)=(x-y)(a+b)(a-b)(a^2+b^2)^2-4a^2b^2=(a+b)

(-3x^y+2xy)-( )=4x^+xy

(-3x^y+2xy)-(4x^+xy)=-3x^y+2xy-4x^-xy=-3x^y+xy-4x^所以填上-3x^y+xy-4x^

化简:[(xy-2)(xy+2)-2x2y2+4]÷(xy).

[(xy-2)(xy+2)-2x2y2+4]÷(xy),=(x2y2-4-2x2y2+4)÷(xy),=(-x2y2)÷(xy),=-xy

x^3y(-4y)^2+(-7xy)^2*(-xy)-5xy^3*(-3x)^2

x^3y(-4y)^2+(-7xy)^2*(-xy)-5xy^3*(-3x)^2=16x^3y^3-49x^3y^3-45^3y^3=-78x^3y^3如果本题有什么不明白可以追问,

-3(2x²-xy)+4(x²+xy-6)

-3(2x²-xy)+4(x²+xy-6)=6x²+3xy+4x²+4xy-24=-2x²+7xy-24

xy^2-2xy+2y-4

xy(y-2)+2(y-2)下步不写了能看懂吧?

分解因式.xy²-2xy+2y-4

原式=xy(y-2)+2(y-2)=(y-2)(xy+2)

已知xx+xy=1,xy-yy=-4,则xx+2xy-yy=

xx+2xy-yy=-3两式相加即可

将xy^-2xy+2y-4因式分解

xy^-2xy+2y-4=xy(y-2)+2(y-2)=(xy+2)(y-2)

-3(2x^2-xy)+4(x^2+xy-6)

-3(2x^2-xy)+4(x^2+xy-6)=-6x^2+3xy+4x^2+4xy-24=-2x^2+7xy-24再问:thankyou~

已知x-y=4xy,则2x+3xy-2yx-2xy-y

∵x-y=4xy,∴2x+3xy-2yx-2xy-y=2(x-y)+3xyx-y-2xy=8xy+3xy4xy-2xy=112.故答案为:112.

3xy-3xy-xy+2yx

3xy-3xy-xy+2yx=-xy+2xy=xy

【(2+xy)(xy-2)-xy(xy+1)+4】/(-2xy) 一道计算题!

=(x²y²-4-x²y²-xy+4)/(-2xy)=-xy/(-2xy)=1/2

5xy^2-[3xy^2-(4xy^2-2x^y)]+x^2y-xy^2如何化简

5xy^2-[3xy^2-(4xy^2-2x^y)]+x^2y-xy^2=5xy^2-3xy^2+(4xy^2-2x^y)+x^2y-xy^2=5xy^2-3xy^2+4xy^2-2x^y+x^2y-

[(xy-2)(-xy-2)-4(xy-1)^2]除以(-xy),其中x=20,y=-25分之1

[(xy-2)(-xy-2)-4(xy-1)^2]除以(-xy)=[-x²y²+4-4(x²y²-2xy+1)]÷(-xy)=(-x²y²+