x2-3xy-10y2 x 9y-2因式分解

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已知x2-xy=-3,2xy-y2=-8,求2x2+4xy-3y2的值.

x2-xy=-3①,2xy-y2=-8②,①×2+②×3得:2x2-2xy+6xy-3y2=-6-24=-30,则2x2+4xy-3y2=-30.

已知x2+xy=3,xy+y2=-2,则2x2-xy-3y2的值为(  )

∵2(x2+xy)-3(xy+y2)=2x2-xy-3y2,∴2x2-xy-3y2=2×3-3×(-2)=12.故选A.

已知x2+xy=-3,xy+y2=7,试求:x2+2xy+y2的值.

∵x2+xy=-3,xy+y2=7,∴(x2+xy)+(xy+y2)=-3+7=4,即x2+2xy+y2=4.

计算:3xy(x2y-xy2+xy)-xy2(2x2-3xy+2x)因式分解

3xy(x²y-xy²+xy)-xy²(2x²-3xy+2x)=3x³y²-3x²y³+3x²y²-

(8xy-3x2)-5xy-3(xy-2x2+3)

A=-6-4+2+1=-7,B=6+4-2+1=9A-2B=-7-2x9=-25

已知x2+xy=3,xy+y2=-2,则2x2-xy-3y2=______.

有x2+xy=3可得,2x2+2xy=6  (1),有xy+y2=-2得,3xy+3y2=-6 (2),根据分析,(1)-(2)可得,2x2-xy-3y2=6-(-6)=

2x2-xy+3y2因式分解

十字相乘法原式=(2x-3y)(x+y)

(2x2-3xy+4y2)+(x2+2xy-3y2)化简(要有过程)

原式=(2x²-3xy+4y²)+(x²+2xy-3y²)=(2x²+x²)+(-3xy+2xy)+(4y²-3y²)=

已知x2-xy=3,xy-y2=-5,试求代数式x2+2xy-3y2的值.

x2+2xy-3y2=x2-xy+3xy-3y2=x2-xy+3(xy-y2),∵x2-xy=3,xy-y2=-5,∴x2+2xy-3y2=3+3×(-5)=-12.

解一个二元二次方程x2-4xy+3y2=0x2=10-y2

x2-4xy+3y2=0因式分解(x-3y)(x-y)=0所以x=3y或者x=y带入第二个式子得到两组解x=3,y=1或者x=y=根号下5

解方程组x2+y2=10,xy=3

答:x²+y²=10xy=3,y=3/x代入上式得:x²+(3/x)²=10整理得:(x²)²-10*x²+9=0(x²

已知6x2减去xy减去15y2等于0,求分式2x2减去3xy减去3y2分之x2减去2xy+4y2

6x2-xy-15y2=(2x+3y)(3x-5y)=0,所以x=-3/2y或x=5/3y

x2 y2+3xy+2 因式分解

x2y2+3xy+2=(xy)^2+3xy+2=(xy+2)(xy+1)很高兴能帮助您~!

X2+3xy+y2因式分解

=[x+(3-√5)/2*y][x-(3-√5)/2*y]有点牵强,但这是唯一的答案了

已知x2;+xy=3,xy+y=-2,求代数式2x2;-xy-3y2;的值

2x²-xy-3y²=2x²+2xy-3xy-3y²=2(x²+xy)-3(xy+y²)已知x²+xy=3,xy+y²=

计算:12xy+(3x2-5xy)-2(3xy+2x2).

原式=12xy+3x2-5xy-6xy-4x2,=xy-x2.

已知X2次方+XY=3,XY+Y2次方=-2,求下例值:2X2次方-XY-3Y2次方

0.X^2+XY=3;(1)XY+Y^2=2;(2)2*(1)-3*(2)=2*X^2-XY-3*Y^2=2*3-3*2=0

已知实数x,y满足x2+xy+y2=3,则x2-xy+y2的最小值

由x2+xy+y2=3得,x^2+y^2=3-xyx^2+y^2≥2xy得,xy≤1所以x^2-xy+y^2=3-2xy≥1等号成立当且仅当x=y=±1

先化简再求值2(x2-xy)-3(2x2-3xy)-2[x2-(2x2-xy+y2)],其中x=-1,y=-2.

原式=2x2-2xy-6x2+9xy-2x2+2x2-xy+y2=-2x2+5xy+2y2,当x=-1,y=-2时,原式=-2+10+8=16.