x-y=5,(10x y (10 x)=143-搜答案-智慧作业帮

（3xy+10y)+[5x--(2xy+2y--3x)]=3xy+10y+5x--2xy--2y+3x=xy+8y+8x=xy+8(x+y)=--2+24=22.看来你在解题目时比较粗心,不知是那里搞

(3xy+10y)+5x-(2xy+2y-3x)=3xy+10y+5x-2xy-2y+3x=xy+8x+8y=-2+8(x+y)=-2+24=22

（3xy+10y)+[+5x-(2xy+2y-3x)]=3xy+10y+[+5x-2xy-2y+3x],[原式去括号]=3xy+10y+5x-2xy-2y+3x,[去括号]=3xy-2xy+5x+3x

[-(xy)/(x-y)^2]^4*[(x^2-xy)/x]^3*x^4/y^10÷[x/(xy-y^2)]^5=(x^4y^4)/(x-y)^8*(x-y)^3*x^4/y^10*[y^5(x-y)

x y xy=10怎么算

2xy=10xy=5

(3xy+10y)+[5x-(2xy+2y-3x)]=3xy+10y+5x-2xy-2y+3x=3xy-2xy+10y-2y+5x+3x=(3xy-2xy)+(10y-2y)+(5x+3x)=xy+8

（5Xy+10y)+[5X-（3Xy+2Y-3x)]=5Y(X+2)+(5X-3XY-2Y+3X)=5YX+10Y+8X-3XY-2Y=2XY+8Y+8X=2*-2+8(x+y)=-4+24=20

直接去括号就是8（x+y）+xy带入得22x用方程组做x是二分之括号三加减根号下十七括号完

原式=3xy+10y+5x-2xy-2y+3x=xy+8y+8x=8（x+y）+xy，当xy=2，x+y=3时，原式=8×3+2=26．

(3xy+2)^2+|7-x-y|=0,则3xy+2=0,7-x-y=0,即x+y=7,xy=-2/3(5xy+10y)-[-5x-(4xy-2y+3x)]=5xy+10y-(-5x-4xy+2y-3

（3xy+10y)+{5x-(2xy+2y-3x)}=3xy+10y+5x-2xy-2y+3x=xy+8x+8y=xy+8(x+y)xy=-2x+y=3xy+8(x+y)=-2+8×3=22

(1)×7+(2)×328y+27y=55xy所以y=0或x=1分别代入所以x=0.y=0x=1,y=1/2

即xy=-2x+y=3原式=3xy+10y+5x-2xy-2y+3x=xy+8x+8y=xy+8(x+y)=-2+8×3=22

xy+yx=10x,y是多少

xy+yx=10x+y+10y+x=11x+11y=100+x10x=100-11yx=10-1.1y所以y只能是0

x^2+10xy+25y^2-1=0（x+5y）²=1→x+5y=1或者x+5y=-1x^3+5x^2y+x^2=x²（x+5y+1）当x+5y=1时,原式=2x²当x+

因为x+y=10所以(x+y)^2=100=x^2+y^2+2xy所以x^2+y^2=100-2xy=90

因为：xy=(x-10)(y+1)→xy=xy+x-10y-10①xy=(x-15)(y+3)→xy=+3x-15y-45②由①、②得：x=10y+10③x=5y+15④将③‐④得：10y+

严重怀疑你掉了(x+3)的平方那个2

(*^__^*)嘻嘻……自己慢慢想吧!用计算器算呗

[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-x)^29^-x*27^y=3^-2x*3^3y=3^(-2x+3y)=3^(-