作业帮X-3分之1-X的平方-9
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（3-x分之x-1）平方÷（x平方-6x+9分之9-x平方）平方*x平方-2x+1分之6+2x=[(x-1)/(3-x)]²÷[(9-x²)/(x²-6x+9)]
是求X的值吗?不晓得对不对哈,姑且一看吧 由已知可得：
原式=1/(x+1)*[(x-3)/(x+3)^2+2/(x+3)]-x/(x+3)(x-3)=1/(x+1)[3(x+1)/(x+3)^2]-x/(x+3)(x-3)=3/(x+3)^2-x/(x+
)【(x²-2x+1)/(x²-1)】÷【(x-1)/(x²+x)】=【(x-1）²/(x+1)（x-1)】÷【(x-1)/x(x+1)】=【(x-1）/(x+
x-3分之5-x方-9分之x-2+2x-6分之x-1=5/(x-3)-(x-2)/(x^2-9)+(x-1)/2(x-3)=(10(x+3)-2(x-2)+(x-1)(x+3))/2(x+3)(x-3
[(x的平方-3x)分之(x+3)-(x的平方-6x+9)分之(x-1)]÷x分之(x-9)=[(x+3)/(x^2-3x)-(x-1)/(x^2-6x+9)])]÷[(x-9)/x]=[(x+3)/
1：2分之3X的平方-{-2分之1X平方}+{-2X平方}=3x²/2+x²/2-2x²=4x²/2-2x²=2x²-2x²=02
x的平方-2x+1分之x-3÷x-1分之x的平方-9=[(x-3)/(x-1)²]*[(x-1)/(x+3)*(x-3)]=1/(x-1)(x+3)
1.x^2+x-1/2x^2-1+x-1=(1/2)x^2+x-1.2.x^2+2x+3/1x^2-9x-12=4x^2-7x-12.3.-x^2+9x-1/20x^2-7x+12=(21/20)x^
(x²+6x+9)分之(x-3)+(9-x²)分之x=(x²+6x+9)分之(x-3)-(x²-9)分之x=(x+3)²分之(x-3)-[(x+3)(
(x²-6x+9)/(x+1)÷(x²-9)/(x²+x)=[(x-3)²/(x+1)]×[x(x+1)/(x+3)(x-3)]=x(x-3)/(x+3)x的平
x平方-x平方=0
x-1/x=3两边平方x^2-2+(1/X)^2=9x^2+(1/X)^2=11
3x的平方+9x的平方没打错?再问：能不能重新拼一遍再答：3x的平方+9x的平方有没有打错吗再问：没有，题目是这个样子的再答：=[（X+3)(X-3)]/(X+3)²×12X²/[
原式=1/(x+1)*[(x-3)/(x+3)^2+2/(x+3)]-x/(x+3)(x-3)=1/(x+1)[3(x+1)/(x+3)^2]-x/(x+3)(x-3)=3/(x+3)^2-x/(x+
x+x分之1=3所以x0X^2-3X+1=0X=(=(3+根号下5)/2或=(3-根号下5)/2x的平方+9x-3分之x的平方=2/3X^2+9x把X^2=1-3x代入得2/3-2X+9x=2/3+7
原式=1/(x-3)-1/2(x+3)-x/(x-3)²=[2(x+3)(x-3)-(x-3)²-2x(x+3)]/[2(x+3)(x-3)²]=(2x²-18
=(x+1)(x-1)/(x+3)²×[-1/(x-1)]×(x+3)/(x²+4)=-(x+1)/(x+3)(x²+4)