x-1分之x-2除于(x 1减x-1分之3
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解题思路:根据等式的性质,等式的两边先同时×1/4,再同时×3/2即可。解题过程:2/3x÷1/4=12解:2/3x÷1/4×1/4=12×1/42/3x=32/3x×3/2=3×3/2x=9/2
x^2-2x-1=0显然x不等于0所以两边可以除以xx-2-1/x=0x-1/x=2两边平方x^2-2+1/x^2=4x^2+1/x^2=6x^3-2x-1/x^3+2/x=(x^3-1/x^3)-2
35分之4x=7分之2(4/35)x=2/7x=2/7×35/4x=5/2x除于8分之3=27分之16x/(3/8)=16/2727x=16×3/827x=6x=2/9x+4分之1=100x+1/4=
(x-1分之x-x+1分之x)除与1-x分之2x=[x/(x-1)-x/(x+1)]÷2x/(1-x)={[x(x+1)-x(x-1)]/(x+1)(x-1)}÷2x/(1-x)=2x/(x+1)(x
x÷3/7=9/14x=9/14×3/7x=27/98
楼主说的除指的是除以吧?3/4x=1/2x=(3/4)/(1/2)=3/2
x=10分之9×1又7分之2x=1又70分之11
X+2分之X*2+4X+4除于(X*2+2X)=(x+2)^2/(x+2)÷(X*2+2X)=(x+2)×1/x(x+2)=1/x=1/√2=√2/2
[x+1-15/(x-1)]÷[(x^2-4x)/(x^2-x)]=[(x^2-1-15)/(x-1)]÷[x(x-4)/x(x-1)]=[(x^2-16)/(x-1)]÷[(x-4)/(x-1)]=
(x-x分之1)除x分之x+1=(x²-1)/x÷(x+1)/x=(x+1)(x-1)÷(x+1)=x-1=√2+1-1=√2本题有什么不明白可以追问,
原式=[(x+2)/x(x-2)-(x-1)/(x-2)²]*x/(x²-4)=[(x+2)(x-2)-x(x-1)]/x(x-2)²*x/(x+2)(x-2)=(x
原式=[(x²-2x)/(x²-1)]÷[(x-1)-(2x-1)/(x+1)]=[(x²-2x)/(x²-1)]÷[(x²-2x)/(x-1)]=[
∵1/(x^2+3x+2)+1/(x^2+5x+6)+1/(x^2+7x+12)=1/(3x),∴1/[(x+1)(x+2)]+1/[(x+2)(x+3)]+1/[(x+3)(x+4)]=1/(3x)
(1-x+2分之1)除于x+2分之x的2次方-1=(1-x+1/2)/x+(x²-1)/2=(3/2-x)/x+(x²-1)/2=3/2x-1+x²/2-1/2=x
答;把x带进去,317/24
原式=[(x+2)/x(x-2)-(x-1)/(x-2)²]÷(4-x)/x=[(x+2)(x-2)/x(x-2)²-x(x-1)/x(x-2)²]÷(4-x)/x=[(
1/4x+2=41/4x=4.2-21/4x=2.2x=2.2÷1/4x=8.8x÷2/15=1/3x=1/3×2/15x=2/45