x+2÷2-2＝3x-1÷5怎么解

原式=[(x+2)/(x^2-2x)-(x-1)/(x^2-4x+4)]÷2(x-4)/(x^3-2x^2)=[(x+2)/(x^2-2x)-(x-1)/(x-2)²)]*[x²(

(x+1-1/1-x)÷(x-x²/x-1)=[(x+1)+1/(x-1)]×[-(x-1)/x(x-1)]=(x²-1+1)/(x-1)×(-1/x)=-x/(x-1)(x-4/

=(x+1)(x-1)/(x+2)²×1/(x+1)×(x+2)(x+1)/(x-1)=(x+1/(x+2)

是这样的：x^5+x^4=x^3(x^2+x)=(x^2+x)[(x^3-1)+1]=(x^2+x)(x^3-1)+x^2+x=[x(x+1)(x-1)](x^2+x+1)+x^2+x=(x^3-x)

A={x|x^2-2x-3<3(1-x)}={x|x^2+x-6<0}={x|-3<x<2}B={x|9-x^2>6-2x}={x|x^2-2x-3<0}={x|-

|x-1|+|x-10|表示数轴上x到1的距离+x到10的距离.显然最小值是9,此时x只要在1到10之间就好.类似的,|x-2|+|x-9|的最小值是7,此时x在2到9之间就好.|x-3|+|x-8|

解题思路：分式的混合运算，按照分式运算法则进行计算。解题过程：

（x+2/x²-2x-x-1/x²-4x+4）÷x-4/x={(x+2)(x-2)/[x(x-2)²]-x(x-1)/[x(x-2)²]}·x/(x-4)={(

是不是[3/(x-1)-x-1]÷[(x-2)/(x²-2x+1)][3/(x-1)-x-1]÷[(x-2)/(x²-2x+1)]={[3-(x²-1)]/(x-1)}÷

注意：本题x=2时题目没意义,应该舍去（这是很多学生错误所在）这里x只能取根号2-1  

x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)

原式=x(x²-2x+3-3)×2/x²=x²(x-2)×2/x²=2x-4

1.(x^3-3x^2)/(x^2+5x+6)÷(x^3-9x)/(x^2+2x-3)*(x+2)/(2x)=x^2(x-3)/(x+2)(x+3)*(x+3)(x-1)/x(x+3)(x-3)*(x

解1：原式=x(x-1)/(x+1)*(x+1)/x=x-1解2：原式=(x+3)^2/(x+3)(x-3)*(x-3)/(x+2)=(x+3)/(x-3)*(x-3)/(x+2)=(x+3)/(x+

①=15x²-10x-x-1=15x²-11x-1②=15x-10-x-1=14x-11①是5x（3x-2）-（x-1）②是5乘（3x-2）-（x-1）你自己选吧

原式化简：{（x-3)(x-2)/(x-3)(x-4)}²÷{(x+1)(x+2)/(x-4)(x+2)}²{(x-2)/(x-4)}²÷{(x+1)/(x-4)}

(1+1/x)÷(2x-1+x²/x)=（1+x）/x÷(2x²-1-x²)/x=(1+x)÷（x²-1）=(1+x)÷(x+1)(x-1)=1/(x-1)2x

x(2-1/x)+x/(x^2-2x)÷(3-x)/(x^2-4)=x((2x-1)/x)+x/(x^2-2x)x(x^2-4)/(3-x)=(2x-1)+(x+2)/(3-x)=(7x-3-2x^2

/>(x+2)/(x+1)-(x+3)/(x+2)-(x+4)/(x+3)+(x+5)/(x+4)=1+1/(x+1)-1-1/(x+2)-1-1/(x+3)+1+1/(x+4)=1/(x+1)-1/