x y=6 xy=2.75 求x-y的值

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已知x-xy=8,xy-y=-9,求x+y-2xy的值

x-xy=8(1)xy-y=-9(2)则有(1)-(2):X-XY-XY+Y=X+Y-2XY=8-(-9)=17

已知x/y=2,求 [x^2-xy+3xy^2 ] / [ x^2+xy+6y^2]的值

因为x/y=2所以x=2y是[x^2-xy+3y^2]/[x^2+xy+6y^2]吧=(4y^2-2y^2+3y^2)/(4y^2+2y^2+6y^2)=5y^2/12y^2=5/12

已知x+y=4,xy=-2,求代数式3(xy+2y)-(xy-6x)的值

原式=3xy+6y-xy+6x=2xy+6(x+y)=2*(-2)+6*4=24-4=20

x^+2xy+y^+4=16 x^-2xy+y^=16 求(3xy+6y^)+|x^-(2xy+2y^-3x^)|的值

x^+2xy+y^+4=16(x+y)²=16-4=12(1)x^-2xy+y^=16(x-y)²=16(2)(1)-(2)2y*2x=-4xy=-1(3xy+6y^)+|x^-(

已知x+y=3,xy=1,求代数式5xy+4x+7y+6x-3xy-4xy+3y的值.

5xy+4x+7y+6x-3xy-4xy+3y=5xy-3xy-4xy+4x+6x+7y+3y=(5-3-4)xy+(4+6)x+(7+3)y=-2xy+10x+10y=-2xy+10(x+y)因为x

若x-y=5,xy=6,求x^2-xy^2和x^2y+xy^2

x=-1,y=-6或x=6,y=1代入式子得x^2-xy^2=37或30x^2y+xy^2=-42或42

若x+y=6,xy=2.75,x-y>0,求x-y的值

(x+y)^2=36x^2+y^2+2xy=36x^2+y^2=36-2*2.75=30.5(x-y)^2=x^2+y^2-2xy=30.5-2*2.75=25x-y=5或者-5已知x-y>0x-y=

2x+y+6=xy,xy为正实数,求xy最小值

xy为正实数,则有2x+y>=2根号(2xy)即:xy-6>=2根号(2xy)设根号(xy)=t>0,则xy=t^2t^2-6>=2根号2tt^2-2根号2t-6>=0(t-3根号2)(t+根号2)>

已知x+y=4,xy=-2,求代数式3(xy+2y)-(xy-6x)

3(xy+2y)-(xy-6x)=3xy+6y-xy+6x=2xy+6(x+y)=2×(-2)+6×4=-4+24=20

已知X+y=6,xy=7 求x^2y+xy^2=

x^2y+xy^2=xy(x+y)=7x6=42再问:��(x+1)^2=13��x^2+2x+3=再答:x^2+2x+3=(x+1)^2+2=13+2=15

若正实数x,y满足2x+y+6=xy,求xy的最小值.

2x+y+6=xy化简得:Y=(2X+6)/(X-1)X不等于0因为正实数x.所以X>0所以X>1函数Y=(2X+6)/(X-1)是单调递增所以X=2为最小值,Y=10所以XY最小值为XY=20

已知X+Y=6,xy=3求代数式(5XY+4X+7Y)+(6X-3XY)-(4XY-3Y)的值

先把代数式(5XY+4X+7Y)+(6X-3XY)-(4XY-3Y)化简(5XY+4X+7Y)+(6X-3XY)-(4XY-3Y)=5XY+4X+7Y+6X-3XY-4XY+3Y=-2XY+10X+1

x-y=3,xy=5,求代数式(7xy+4x-7y)+(6x-3xy)-(3y+4xy)的值

(7xy+4x-7y)+(6x-3xy)-(3y+4xy)=7xy+4x-7y+6x-3xy-3y-4xy=10x-10y=10(x-y)=10*3=30

x+y=8,xy=-2,求(5xy+4x+7y)+(6x-3xy)-(4xy-3y)的值

(5xy+4x+7y)+(6x-3xy)-(4xy-3y)=5xy+4x+7y+6x-3xy-4xy+3y=(5xy-3xy-4xy)+(4x+6x)+(7y+3y)=-2xy+10x+10y=-2x

已知xy/x+y=6,求3x-2xy+3y/-x+3xy-y的值.

xy/x+y=6∴xy=6(x+y)3x-2xy+3y/-x+3xy-y=[3x-12(x+y)+3y]/[-x+18(x+y)-y]=-9(x+y)/17(x+y)=-9/17再问:你在啊?再答:在

已知x+xy=-2,xy-y=-6求代数式2x{-4y-3[(x+xy)²+x]-½[(y-xy

已知x+xy=-2,xy-y=-6则X+Y=42x{-4y-3[(x+xy)²+x]-½[(y-xy)²-2y]=2x{-4y-3[(-2)²+x]-&fr

如果xy+x+y=6,试求自然数 xy

已知xy+x+y=6则xy+x+y+1=(x+1)(y+1)=7=7×1因为x,y都是自然数(非负整数)所以x+1,y+1≥1所以只能x+1=7y+1=1即x=6,y=0或x+1=1,y+1=7即x=

若x+y=5,xy=6,求x^2y+xy^2的值

x^2y+xy^2=xy×(x+y)=6×5=30