x 3分之1 x的平方-9分之6等于多少

（3-x分之x-1）平方÷（x平方-6x+9分之9-x平方）平方*x平方-2x+1分之6+2x=[(x-1)/(3-x)]²÷[(9-x²)/(x²-6x+9)]

是求X的值吗?不晓得对不对哈,姑且一看吧　　由已知可得：

①49分之1的x的平方-25分之16y的平方=（x/7+4y/5）（x/7-4y/5）②-0.01+四分之九（a的平方）=(3a/2-0.1)(3a/2+0.1)③49（a-b）的平方-16（a+b）

x+3分之x+x平方-9分之6等于x-3分之1两边乘（x+3）（x-3）x(x-3)+6=x+3x²-3x+6=x+3x²-4x+3=0(x-3)(x-1)=0x1=3x2=1由于

由于1/(x^2-x+1)=1/6则x^2-x+1=6再由求根公式求出x,代入后面式子计算

x的平方-9分之1-x-3分之1除以x-1分之6+2x=1/(x^2-9)-1/(x-3)*(x-1)/2(3+x)=(2-(x-1))/2(x^2-9)=(3-x)/2(x^2-9)=-(x-3)/

1/3[1/x--1/(x+3)]+1/3[1/(x+3)--1/(x+6)]+1/3[1/(x+6)--1/(x+9)]=1/(x^2+18)1/x--1/(x+9)=3/(x^2+18)(x+9)

原式=1/(x+1)*[(x-3)/(x+3)^2+2/(x+3)]-x/(x+3)(x-3)=1/(x+1)[3(x+1)/(x+3)^2]-x/(x+3)(x-3)=3/(x+3)^2-x/(x+

=2(x-3)/(x+3)(x-3)+(x+1)²/(x+3)(x-2)×(x-2)/(x+1)=2/(x+3)+(x+1)/(x+3)=(x+3)/(x+3)=1

x-3分之5-x方-9分之x-2+2x-6分之x-1=5/(x-3)-(x-2)/(x^2-9)+(x-1)/2(x-3)=(10(x+3)-2(x-2)+(x-1)(x+3))/2(x+3)(x-3

[(x的平方-3x)分之(x+3)-(x的平方-6x+9)分之(x-1)]÷x分之(x-9)=[(x+3)/(x^2-3x)-(x-1)/(x^2-6x+9)])]÷[(x-9)/x]=[(x+3)/

2152+64/x(A+B)C=AC+BC(A-B)C=AC-BC不知道有没用

(x²+6x+9)分之(x-3)+(9-x²)分之x=(x²+6x+9)分之(x-3)-(x²-9)分之x=(x+3)²分之(x-3)-[(x+3)(

x+2/（x的平方-2x）-（x-1）/（x的平方-4x+4）=x+2/（x(x-2)）-（x-1）/（x-2）^2=(x^2-4-(x^2-x))/x(x-2)^2=(x-4)/x(x-2)^2

(x²-6x+9)/(x+1)÷(x²-9)/(x²+x)=[(x-3)²/(x+1)]×[x(x+1)/(x+3)(x-3)]=x(x-3)/(x+3)x的平

原式=1/(x+1)*[(x-3)/(x+3)^2+2/(x+3)]-x/(x+3)(x-3)=1/(x+1)[3(x+1)/(x+3)^2]-x/(x+3)(x-3)=3/(x+3)^2-x/(x+

原式=1/(x-3)-1/2(x+3)-x/(x-3)²=[2(x+3)(x-3)-(x-3)²-2x(x+3)]/[2(x+3)(x-3)²]=(2x²-18

7/x(x+1)-6/(x+1)(x-1)=-1/x(x-1)两边乘以x(x+1)(x-1)得7(x-1)-6x=-(x+1)7x-7-6x=-x-12x=6∴x=3经检验：x=3是方程的解

原式=6/x^2-9-x-1/6-x2=1/2即12+(x-1)(x+3)/2(x+3)(x-3)=1/2即(x-3)(x+4)=0∴x=3(舍)或x=-4很高兴为您解答,【学习宝典】团队为您答题.请

两边乘以x(x-1)得3(x-1)+6x=73x-3+6x=79x=10x=10/9经检验：x=10/9是方程的解