vb,l利用随机函数生成15个10-100之间额整数,然后用选择法
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PrivateSubCommand1_Click()RandomizeDima(10)AsInteger,imasasinteger,iminasinteger,Averageasintegerima
PrivateSubCommand1_Click()Dimi,max,min,sAsIntegermax=0min=100s=0Dima(30)AsIntegerText1.Text=""Text2.
dima,max,min,sum,averagesum=0max=20min=50fori=1to20a=(Rnd*50)+50sum=sum+aifamaxthenmax=aprintanextpr
PrivateSubForm_click()Dimn(1To20)AsIntegerDimi,j,ave,tempRandomizeFori=1To20n(i)=Int((51*Rnd)+50)Pri
Dima(1To20)AsIntegerPrivateSubCommand1_Click()ClsScale(0,0)-(100,100)Foru=1To20a(u)=Int(Rnd*50)+50b=
PrivateSubForm_Click()Dima(19)AsIntegerDimmaxAsInteger,minAsInteger,avAsIntegerFori=0To19a(i)=Int((1
先在窗体上添加一个TextBox文本框(将其Multiline属性设置为True,并调整宽高以便能较好的显示出100个随机数)和一个Button按钮.然后双击Button按钮跳转到代码编辑窗口,粘帖以
PrivateSubCommand1_Click()DimIAsInteger,NAsInteger,MaxAsInteger,MinAsIntegerMin=100RandomizeForI=1To
privatesubcommand1_click()fori=1to15randomizea=int(Rnd*20)+80ifi=1thenmax=a:min=aifmaxathenmin=aprin
我已经上机验证过了,正确.思路:产生80个随机数,把这80个随机数由小到大排序,然后从第1个到第80个的顺序挑选偶数,赋值给字符串s1,够10个换行.再从第80个到第1个的顺序挑选奇数,赋值给字符串s
Dimk%Dima%(1To10)PrivateSubCommand1_Click()Fori=1To10Randomizea(i)=Int(Rnd*100+1)NextPrint"a数组:"k=1F
Dima%(1To6,1To6),b%(1To6,1To6)PrivateSubCommand1_Click()Fori=1To5Forj=1To5a(i,j)=Int(Rnd*90+10)Pictu
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#include#include#include#defineMAX100voidqicksort(int*a,int,int);voidchoosesort(int*a,int,int);voidi
前些天我才写的,是给别人弄的,他要的是1到100的十个数,并且按command2可以到换,我稍加修改给你(别忘了把窗体拉长点哈!短了后面不能显示哦)还要添加一个commandPrivateSubCom
PrivateSubCommand1_Click()Dima(29)AsInteger,tmpAsIntegerDimiAsInteger,jAsIntegerRandomizeTimeFori=0T
PrivateSubCommand1_Click()Dimk,a(1To30)Fori=1To30a(i)=Int(Rnd*800+100)Forj=1Toi-1Ifa(i)=a(j)Theni=i-
dima(30)fori=1to30a(i)=int(rnd(97+3))ifisprime(a(i))=truethenprinta(i);nextifunctionisprime(xasinteg
int(a)是返回一个小于或等于a的整数.rnd*90也就是产生0-90之间的数,不包括0和99.rnd*90+10是产生10-100之间的数,不包括10和100.int(rnd*90)是产生0-89