1.5(x-4)-0.4(2x-3)
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(x-1)^3(x+1)(x-2)/(x+4)
看来是因式分解题目(x+1)(x+2)(x+3)(x+4)+1=(x+1)(x+4)(x+2)(x+3)+1=(x^2+5x+4)(x^2+5x+6)+1=(x^2+5x)^2+10(x^2+5x)+24+1=(x^2+5x+5)^2(x+
(1)6+2(x-3)=X6+2x-6=x2x-x=0x=0(2)8-2(x-7)=x-(x-4)8-2x+14=x-x+4-2x=-18x=9(3)2x-(1.5x-1)=2(1.5x-1)2x-3(1.5x-1)=02x-4.5x=-3
(x+2/x+1)-(x+4/x+3)-(x+3/x+2)+(x+5/x+4)=[(x+1/x+1)+(1/x+1)]-[(x+3/x+3)+(1/x+3)]-[(x+2/x+2)+(1/x+2)]+[(x+4/x+4)+(1/x+4)]=
分子因式分解(x²+4x+4+1)/(x+2)-(x²+6x+9+1)/(x+3)+1=[(x+2)²+1]/(x+2)-[(x+3)²+1]/(x+3)+1=(x+2)+1/(x+2)-(x+3)-
(x+8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3)[(x-8)(x-4)-(x-9)(x-3)]/(x-3)(x-4)=[(x+7)(x+3)-(x+2)(x+8)]/(x+8)(x+3)解得5/
1)(x-3)/(x-2)-(x-5)/(x-4)=(x-7)/(x-6)-(x-9)/(x-8)化简得【(x-3)(x-4)-(x-5)/(x-2)】/【(x-2)(x-4)】=【(x-7)(x-8)-(x-9)(x-6)】/【(x-6)
解-x²(-x)³+3x³(-x²)-4(-x)(-x)^4=x^5-3x^5+4x^5=(1-3+4)x^5=2x^5
/>(x+2)/(x+1)-(x+3)/(x+2)-(x+4)/(x+3)+(x+5)/(x+4)=1+1/(x+1)-1-1/(x+2)-1-1/(x+3)+1+1/(x+4)=1/(x+1)-1/(x+2)-1/(x+3)+1/(x+4
是这样的:x^5+x^4=x^3(x^2+x)=(x^2+x)[(x^3-1)+1]=(x^2+x)(x^3-1)+x^2+x=[x(x+1)(x-1)](x^2+x+1)+x^2+x=(x^3-x)(x^2+x+1)+x^2+x
不知道你^这个符号什么意思暂且当成平方做吧x^2+4x+3=(x+1)(x+3)(2x-x)^2=x^2x^2+x=x(x+1)x^2+x-6=(x+3)(x-2)约分:得x/(x-2)再问:题目炒错了,不好意思..原题(x^+4x+3)(
设x1=4-√3,x2=4+√3,是方程X^2-8X+13=0的两根所以X1^2-8X1+15=2X^4-6X^3-2X^2+18X+23=(X+1)^2*(X^2-8X+13)+10=10所以原式=10/2=5
前两题太恐怖了第一题的话,是不是有笔误啊第二题给个思路右边是等比数列,运用公式,化简得8[(1.5^x)-1]然后用数学工具算出左右两个函数的交点第三题写一下Sn=(1-5)+(9-13)+...发现了吧,所以S22=(-4)*11=-44
=2(x-3)/(x-2)²×1/(x+3)×(x+3)(x-2)/(x+3)=2(x-3)/(x-2)(x+3)=(2x-6)/(x²+x-6)感觉有一个你式子中的某一个+3应该是-3
=(x+1)(x-1)/(x+2)²×1/(x+1)×(x+2)(x+1)/(x-1)=(x+1/(x+2)
先通分,通下来原式=[3x(x-2)-x(x+2)+2x]/(x+2)(x-2),再化简=2x(x-3)/(x+2)(x-2),(这里有点奇怪,凭我多年来做题的经验,这里应该都是可以约掉的,你看时要看下你题写错了没,反正仅供你参考的),然后
1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+...+1/(x+2005)(x+2006)=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)+.+1/(x+200
(2x-6)/(x²-4)/(X+3)*(x²+x-6)/(3-x)=2(x-3)/[(x+2)(x-2)(x+3)]*(x+3)(x-2)/(3-x)=-2/(x+2)
|x-1|+|x-10|表示数轴上x到1的距离+x到10的距离.显然最小值是9,此时x只要在1到10之间就好.类似的,|x-2|+|x-9|的最小值是7,此时x在2到9之间就好.|x-3|+|x-8|的最小值是5,此时x在3到8之间就好.|
x(1+2+...+9)=x(9-8-7-...-1)x=0记得采纳啊