．用串输入一篇短文,统计其中所出现的单词的频率(单词间以空格隔开).

#includemain(){intt,i,c0=0,c1=0,c2=0;for(i=0;i

publicstaticvoidmain(String[]args)\x05{\x05\x05System.out.println("请输入英语片段,以';'结束:");\x05\x05Scanner

publicstaticvoidmain(String[]args){Scannersc=newScanner(System.in);System.out.println("请输入10个整数");St

非要限制输入的大小么?过会儿给你发个#include#includevoidmain(){charm_input;intdigit=0,space=0,others=0,uppercase=0,low

下面这句有错：for(i=0;i

找篇英语文章变成txt文本放到project文件夹里,用文件流读取单词到数组,对单词排序,然后对排序后的数组循环一遍,统计同一的单词的数,如你统计到后来的一个单词出现的次数大于前一个把计数变量的数的整

#include#includevoidmain(){charsen[256];intben=0,men=0,spa=0,num=0,oth=0;inti;gets(sen);for(i=0;i='A

#includemain(){intletter=0,number=0,blank=0,other=0;\\分别用来统计字母,数字,空格和其它字符的个数charc;\\用来读取字符while((c=g

#includevoidmain(){charline[30];inti,count1=0,count2=0,count3=0,count4=0;printf("\n请输入一行字符:");gets(l

这两个我测试过,符合你的问题一个是数组,一个是指针,选用指针好些.#includeintmain(){intnum=0,word=0,i=0;charstr[40];gets(str);while(s

你弄的太乱,我整理了一下：#includemain(){charstring[81];inti,num=0,word=0;charc;gets(string);for(i=0;(c=string[i]

#includevoidmain(){\x09intletter,space,number,other;\x09charch;\x09letter=space=number=other=0;\x09w

#includevoidmain(){charc;intletter=0;printf("请输入一行字符:\n");while((c=getchar())!='\n'){if(c>='a'&&c='A

#include#include#include#includeusingnamespacestd;main(){stringstr;mapm;do{cin>>str;pairret=m.insert

#includevoidmain(){inta,b,i,j,t,k=0;printf("请输入两个正整数:");scanf("%d%d",&a,&b);if(a>b){t=a;a=b;b=t;}for

#includevoidmain(){intc1=0,c2=0,c3=0,a[10],*p;printf("输入10个整数\n");for(p=a;p0)c1++;elseif(*p

我写了个程序你可以看看：#include#includeintmain(){inti;char*ch;intsum=0;//统计单词个数printf("pleaseinterthe*ch:\n");g

#include"stdio.h"voidmain(){inta[62][2],max,d;inti,j,t;charstring[2500],c;j=64;for(i=0;i

Lookatthegirlinwhite.Shewantedtobeahousewifeinherchildhood.Shethoughthousewifemusthavearegularlife--

SETTALKOFFCLEARCLOSEALLSTORE0TOl,j,kFORi=1TO20input"pleaseinputanumber:"toaIFa>0l=l+1ELSEIFa=0j=j+1E