随机产生100个0-9之间的整数,统计一共产生了多少个0,多少个1

PrivateSubForm_Load()Dima(10),i,x,jAsIntegerDimyAsStringFori=0To9Randomizea(i)=Int(Rnd(1)*101)x=x+a(

a1:a10=randbetween(30,100)最大值=max(a1:a10)最小值=min(a1:a10)平均值=average(a1:a10)

PrivateSubCommand1_Click()RandomizeDima(10)AsInteger,imasasinteger,iminasinteger,Averageasintegerima

PrivateSubForm_Click()Dima(19)AsIntegerDimmaxAsInteger,minAsInteger,avAsIntegerFori=0To19a(i)=Int((1

先在窗体上添加一个TextBox文本框（将其Multiline属性设置为True,并调整宽高以便能较好的显示出100个随机数）和一个Button按钮.然后双击Button按钮跳转到代码编辑窗口,粘帖以

?STR(A(I),3)改为?STR(A(i),3)?"最大数是："+Mmax+"最小数是：",Mmin改为：?"最大数是：",Mmax,"最小数是：",Mmin

帮你写好了,这个是工程文件,下载下来就可以了.以下是源码:PrivateSubCommand1_Click()DimA(10)AsDouble,LAsInteger,BAsDouble,CAsDoub

PrivateSubCommand1_Click()DimIAsInteger,NAsInteger,MaxAsInteger,MinAsIntegerMin=100RandomizeForI=1To

Dima(10)Fori=0To9a(i)=Int(100+100*Rnd)NextiFori=0To8Forj=iTo9Ifa(i)t=a(i)a(i)=a(j)a(j)=tEndIfNextjNe

我已经上机验证过了,正确.思路：产生80个随机数,把这80个随机数由小到大排序,然后从第1个到第80个的顺序挑选偶数,赋值给字符串s1,够10个换行.再从第80个到第1个的顺序挑选奇数,赋值给字符串s

#includevoidmain(){inta[100],i;for(i=0;i

PrivateSubCommand1_Click()DimiAsInteger,nAsInteger,mAsIntegerFori=1To50n=Int(1+Rnd*100)IfnPrintn;m=m

PrivateSubCommand1_Click()Dima(100)AsInteger,xAsIntegerFori=1To100Ifsushu(i)ThenPrinti;IfiMod10=0The

再问：谢了，能否把程序给提供一下，我不会再答：好吧！

dima(9)asintegerprivatesubcommand1_click()dimiasintegerrandomizefori=0to9a(i)=int(rnd*101)text1.text

通过SubMain启动Submain()Dima(9)AsInteger,pAsDouble,iAsInteger,nAsIntegerp=0n=0Fori=0To9a(i)=Rnd*100p=p+a

#include<stdio.h>#include<stdlib.h>#include<time.h>#defineM20voidmain(){inta[M],i;

选择法：PrivateSubForm_Click()Dimi%,j%,a%(1To10)RandomizeFori=1To10a(i)=Int(101*Rnd)NextiFori=1To9k=iFor

PrivateSubCommand1_Click()DimiAsInteger,xAsInteger,sAsLongRandomizeFori=1To30x=Int(Rnd*100)+1Printx,

Option ExplicitPrivate Sub Form_Load()RandomizeMe.AutoRedraw = TrueDim